교과서 질문
The liquids 1-butanol and butanal have similar molar masses. Which is expected to have the higher boiling point? Explain your choices.
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Ch.15 Aldehydes and Ketones
McMurry8th EditionFundamentals of General, Organic, and Biological ChemistryISBN: 9780134015187
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TOC.tableOfContents
- Ch.1 Matter and Measurements27
- Ch.2 Atoms and the Periodic Table20
- Ch.3 Ionic Compounds8
- Ch.4 Molecular Compounds23
- Ch.5 Classification & Balancing of Chemical Reactions12
- Ch.6 Chemical Reactions: Mole and Mass Relationships28
- Ch.7 Chemical Reactions: Energy, Rate and Equilibrium64
- Ch.8 Gases, Liquids and Solids24
- Ch.9 Solutions52
- Ch.10 Acids and Bases25
- Ch.11 Nuclear Chemistry22
- Ch.12 Introduction to Organic Chemistry: Alkanes57
- Ch.13 Alkenes, Alkynes, and Aromatic Compounds47
- Ch.14 Some Compounds with Oxygen, Sulfur, or a Halogen50
- Ch.15 Aldehydes and Ketones45
- Ch.16 Amines42
- Ch.17 Carboxylic Acids and Their Derivatives57
- Ch.18 Amino Acids and Proteins82
- Ch.19 Enzymes and Vitamins63
- Ch.20 Carbohydrates44
- Ch.21 The Generation of Biochemical Energy65
- Ch.22 Carbohydrate Metabolism45
- Ch.23 Lipids42
- Ch.24 Lipid Metabolism33
- Ch.25 Protein and Amino Acid Metabolism24
- Ch.26 Nucleic Acids and Protein Synthesis45
McMurry8th EditionFundamentals of General, Organic, and Biological ChemistryISBN: 9780134015187당신이 사용하는 게 아니라요?교과서 변경
15장, 문제 64
In Problem 15.24, you were given the structure of the free aldehyde form of glucose. Try to draw the two cyclic hemiacetal forms of glucose you would get if (a) the OH on C4 formed the ring and (b) the OH on C3 formed the ring.
검증된 단계별 안내1
Understand the problem: Glucose can form cyclic hemiacetal structures when the aldehyde group on C1 reacts with a hydroxyl group on another carbon atom. In this case, we are tasked with forming two cyclic structures: one where the OH on C4 forms the ring and another where the OH on C3 forms the ring.
Step 1: Recall the structure of glucose in its open-chain form. Glucose is an aldohexose, meaning it has an aldehyde group (-CHO) on C1 and hydroxyl groups (-OH) on carbons C2 through C6.
Step 2: For part (a), identify the OH group on C4. To form a cyclic hemiacetal, the oxygen atom of the OH group on C4 will attack the carbonyl carbon (C1). This reaction forms a six-membered ring (a pyranose structure). Draw the resulting structure, ensuring that the new bond between C1 and the oxygen of C4 is shown, and adjust the stereochemistry of the substituents accordingly.
Step 3: For part (b), identify the OH group on C3. In this case, the oxygen atom of the OH group on C3 will attack the carbonyl carbon (C1). This reaction forms a five-membered ring (a furanose structure). Draw the resulting structure, showing the new bond between C1 and the oxygen of C3, and adjust the stereochemistry of the substituents as needed.
Step 4: Label the anomeric carbon (C1) in both structures. The anomeric carbon is the carbon that was originally part of the carbonyl group. Depending on the orientation of the substituents around the anomeric carbon, you may have two possible anomers (α and β) for each cyclic form. Indicate these possibilities in your drawings.
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주요 개념
질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.
Aldehyde Structure of Glucose
Glucose is a simple sugar that can exist in an open-chain form as an aldehyde. In this form, it has a carbonyl group (C=O) at the first carbon atom, which is crucial for understanding its reactivity and ability to form cyclic structures. The aldehyde group plays a significant role in the formation of hemiacetals when glucose reacts with its hydroxyl groups.
추천 영상:
가이드 코스
0:34
Naming Aldehydes Example 2
Cyclic Hemiacetal Formation
Cyclic hemiacetals are formed when a hydroxyl group reacts with the carbonyl group of an aldehyde, resulting in a ring structure. In glucose, this process can occur at different carbon atoms, leading to different cyclic forms. The position of the hydroxyl group that reacts determines whether the ring closes at C3 or C4, resulting in distinct anomeric forms of glucose.
추천 영상:
가이드 코스
2:55Cyclic Hemiacetals Concept 2
Anomeric Carbon
The anomeric carbon is the carbon atom in a sugar that becomes a new chiral center when the sugar cyclizes. In glucose, the anomeric carbon is C1, which can exist in two configurations (alpha and beta) depending on the orientation of the hydroxyl group attached to it. Understanding the concept of the anomeric carbon is essential for predicting the properties and reactivity of the cyclic forms of glucose.
추천 영상:
가이드 코스
5:36Amino Acid Catabolism: Carbon Atoms Concept 2