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Ch. 14 - Ethers, Epoxides, and Thioethers
Wade - Organic Chemistry 9th Edition
Wade9th EditionOrganic ChemistryISBN: 9780135213728당신이 사용하는 게 아니라요?교과서 변경
14장, 문제 11a

Explain why bimolecular condensation is a poor method for making unsymmetrical ethers such as ethyl methyl ether.

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Bimolecular condensation typically involves the reaction of two alcohol molecules in the presence of an acid catalyst to form an ether and water. This process is also known as the Williamson ether synthesis.
In the case of unsymmetrical ethers like ethyl methyl ether, the reaction involves two different alcohols (e.g., ethanol and methanol). However, when both alcohols are present in the reaction mixture, they can react in multiple combinations, leading to a mixture of products.
The possible products include symmetrical ethers (e.g., diethyl ether and dimethyl ether) as well as the desired unsymmetrical ether (e.g., ethyl methyl ether). This lack of selectivity makes it difficult to isolate the desired product in high yield.
Additionally, the reaction conditions (acidic medium and heat) can lead to side reactions such as dehydration of alcohols to form alkenes or further reactions of the formed ethers, reducing the efficiency of the process.
For these reasons, bimolecular condensation is not an ideal method for synthesizing unsymmetrical ethers. Alternative methods, such as the Williamson ether synthesis using alkoxide ions and alkyl halides, are preferred for better selectivity and yield.

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주요 개념

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Bimolecular Condensation Reaction

Bimolecular condensation reactions involve the reaction of two different reactants to form a product while eliminating a small molecule, typically water. This process often requires specific conditions and can lead to the formation of symmetrical products when the reactants are similar, making it less effective for creating unsymmetrical ethers.
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Condensation Reactions

Unsymmetrical Ethers

Unsymmetrical ethers are compounds where the two alkyl or aryl groups attached to the oxygen atom are different. The synthesis of unsymmetrical ethers often requires selective reactions that favor the formation of one specific ether over another, which is challenging in bimolecular condensation due to the equal reactivity of the reactants.
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How to predict the products of Ether Cleavage.

Selectivity in Organic Synthesis

Selectivity in organic synthesis refers to the ability to preferentially produce one product over others in a chemical reaction. In the case of making unsymmetrical ethers, achieving high selectivity is crucial, and bimolecular condensation often lacks the necessary control, leading to a mixture of products rather than the desired unsymmetrical ether.
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Synthesis of Amino Acids: Strecker Synthesis Example 1
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교과서 질문

Show how the following ethers might be synthesized using (1) alkoxymercuration– demercuration and (2) the Williamson synthesis. (When one of these methods cannot be used for the given ether, point out why it will not work.)

(d) 1-methoxy-1-methylcyclopentane

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교과서 질문

Which of the following ethers can be formed in good yield by condensation of the corresponding alcohols? For those that cannot be formed by condensation, suggest an alternative method that will work.

(a) dibutyl ether

(b) ethyl n-propyl ether

(c) di-sec-butyl ether

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교과서 질문

Show how the following ethers might be synthesized using (1) alkoxymercuration–demercuration and (2) the Williamson synthesis. (When one of these methods cannot be used for the given ether, point out why it will not work.)

f. tert-butyl phenyl ether

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교과서 질문

Show how the following ethers might be synthesized using (1) alkoxymercuration– demercuration and (2) the Williamson synthesis. (When one of these methods cannot be used for the given ether, point out why it will not work.)

(e) 1-isopropoxy-1-methylcyclopentane

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교과서 질문

Propose a mechanism for the following reaction.

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교과서 질문

Propose a mechanism for the acid-catalyzed condensation of n-propyl alcohol to n-propyl ether, as shown above. When the temperature is allowed to rise too high, propene is formed. Propose a mechanism for the formation of propene, and explain why it is favored at higher temperatures.

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