When 3-chlorocyclopropene is treated with AgBF4, AgCl precipitates. The organic product can be obtained as a crystalline material, soluble in polar solvents such as nitromethane but insoluble in hexane. When the crystalline material is dissolved in nitromethane containing KCl, the original 3-chlorocyclopropene is regenerated. Determine the structure of the crystalline material, and write equations for its formation and its reaction with chloride ion.
Ch. 16 - Aromatic Compounds
16장, 문제 16a,b
a. Explain how pyrrole is isoelectronic with the cyclopentadienyl anion.
b. Specifically, what is the difference between the cyclopentadienyl anion and pyrrole?
검증된 단계별 안내1
Step 1: Understand the term 'isoelectronic'. Isoelectronic species have the same number of electrons and similar electronic structures. In this case, pyrrole (Structure 2) and the cyclopentadienyl anion (Structure 1) are being compared.
Step 2: Analyze the cyclopentadienyl anion (Structure 1). It is a five-membered ring with a negative charge on one of the carbons. The negative charge contributes two electrons to the π-system, and the remaining carbons each contribute one electron, resulting in a total of 6 π-electrons. This satisfies the Hückel rule for aromaticity (4n+2 π-electrons, where n=1).
Step 3: Analyze pyrrole (Structure 2). Pyrrole is a five-membered ring containing a nitrogen atom. The nitrogen atom has a lone pair of electrons that are delocalized into the π-system, contributing two electrons. The remaining carbons each contribute one electron, resulting in a total of 6 π-electrons, making pyrrole aromatic and isoelectronic with the cyclopentadienyl anion.
Step 4: Compare the structural difference between the cyclopentadienyl anion and pyrrole. The cyclopentadienyl anion has a negative charge on one of its carbons, while pyrrole has a nitrogen atom in place of one of the carbons. The nitrogen atom contributes its lone pair to the π-system, whereas the negative charge on the cyclopentadienyl anion contributes electrons to the π-system.
Step 5: Summarize the key difference. The cyclopentadienyl anion achieves aromaticity through a negative charge on a carbon atom, while pyrrole achieves aromaticity through the lone pair of electrons on the nitrogen atom. Both structures are aromatic and isoelectronic, having 6 π-electrons in their conjugated systems.

비슷한 문제에 대한 검증된 영상 답변:
이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
영상 길이:
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주요 개념
질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.
Isoelectronic Species
Isoelectronic species are atoms, ions, or molecules that have the same number of electrons and, consequently, the same electronic structure. In this case, pyrrole and the cyclopentadienyl anion both have a total of 6 valence electrons, which allows them to exhibit similar bonding characteristics despite differing in structure and overall charge.
추천 영상:
가이드 코스
Base Pairing Concept 2
Aromaticity
Aromaticity refers to the enhanced stability of certain cyclic compounds due to the delocalization of π electrons across the ring structure. Both pyrrole and the cyclopentadienyl anion are aromatic, which contributes to their stability and unique chemical properties, despite the presence of different atoms (nitrogen in pyrrole and a negative charge in the anion).
추천 영상:
Intro to Aromaticity
Structural Differences
The cyclopentadienyl anion (Structure 1) has a negative charge localized on one of the carbon atoms, while pyrrole (Structure 2) contains a nitrogen atom that contributes to the π system. This difference in atom type and charge distribution affects their reactivity and interactions with other chemical species, despite their isoelectronic nature.
추천 영상:
How bondline is different from Lewis Structures.
관련 실천
교과서 질문
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교과서 질문
Explain why each compound is aromatic, antiaromatic, or nonaromatic.
(a)
(b)
(c)
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교과서 질문
Show which of the nitrogen atoms in purine are basic, and which one is not basic. For the nonbasic nitrogen, explain why its nonbonding electrons are not easily available to become protonated.
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교과서 질문
The following hydrocarbon has an unusually large dipole moment. Explain how a large dipole moment might arise.
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교과서 질문
The polarization of a carbonyl group can be represented by a pair of resonance structures:
Cyclopropenone and cycloheptatrienone are more stable than anticipated. Cyclopentadienone, however, is relatively unstable and rapidly undergoes a Diels–Alder dimerization. Explain.
1130
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교과서 질문
Draw resonance forms to show the charge distribution on the pyrrole structure.
1647
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