Question

Draw the structure of a four-residue segment of DNA with the following sequence. (3′end) G-T-A-C (5′ end)

Accepted Answer

Understand the problem: You are tasked with drawing a four-residue segment of DNA with the sequence G-T-A-C, starting from the 3′ end and ending at the 5′ end. DNA is composed of nucleotides, each containing a sugar (deoxyribose), a phosphate group, and a nitrogenous base (Guanine, Thymine, Adenine, Cytosine). Step 1: Begin by drawing the backbone of the DNA strand. The backbone consists of alternating deoxyribose sugars and phosphate groups. Each sugar is connected to the next via a phosphodiester bond, which links the 3′ hydroxyl group of one sugar to the 5′ phosphate group of the next sugar. Step 2: Attach the nitrogenous bases to the 1′ carbon of each deoxyribose sugar. For the given sequence (3′ end G-T-A-C 5′ end), attach Guanine (G) to the first sugar, Thymine (T) to the second sugar, Adenine (A) to the third sugar, and Cytosine (C) to the fourth sugar. Step 3: Ensure the correct orientation of the strand. The 3′ end of the DNA strand should have a free hydroxyl (-OH) group on the 3′ carbon of the first sugar, and the 5′ end should have a free phosphate group attached to the 5′ carbon of the last sugar. Step 4: Double-check the structure for accuracy. Verify that the phosphodiester bonds are correctly formed, the bases are properly attached to the sugars, and the strand is oriented from 3′ to 5′ as specified in the problem.

Draw the structure of a four-residue segment of DNA with the following sequence. (3′end) G-T-A-C (5′ end)

비슷한 문제에 대한 검증된 영상 답변:

주요 개념

DNA Structure

Base Pairing

Directionality of DNA Strands