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Ch. 8 - Hypothesis Testing with Two Samples
Larson - Elementary Statistics: Picturing the World 8th Edition
Larson8th EditionElementary Statistics: Picturing the WorldISBN: 9780137493470Not the one you use?Change textbook
Chapter 8, Problem 8.T.2c

Take this test as you would take a test in class.For each exercise, perform the steps below.

c.Find the critical value(s) and identify the rejection region(s).




A real estate agency says that the mean home sales price in Olathe, Kansas, is greater than in Rolla, Missouri. The mean home sales price for 39 homes in Olathe is \$392,453. Assume the population standard deviation is \$224,902. The mean home sales price for 38 homes in Rolla is \$285,787. Assume the population standard deviation is \$330,578. At α=0.05, is there enough evidence to support the agency’s claim? (Adapted from Realtor.com)

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Identify the type of test and the hypotheses. Since the agency claims that the mean home sales price in Olathe is greater than in Rolla, this is a right-tailed test. The null hypothesis is \(H_0: \mu_{Olathe} \leq \mu_{Rolla}\) and the alternative hypothesis is \(H_a: \mu_{Olathe} > \mu_{Rolla}\).
Determine the significance level \(\alpha = 0.05\) and the type of test statistic to use. Because the population standard deviations are known, use the Z-test for the difference between two means.
Find the critical value for a right-tailed Z-test at \(\alpha = 0.05\). This critical value corresponds to the Z-score where the area to the right is 0.05.
Define the rejection region based on the critical value. For a right-tailed test, the rejection region is all Z-scores greater than the critical value.
Summarize: If the calculated test statistic exceeds the critical value, reject the null hypothesis; otherwise, do not reject it.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Hypothesis Testing

Hypothesis testing is a statistical method used to decide whether there is enough evidence to support a specific claim about a population parameter. It involves formulating a null hypothesis (no effect or difference) and an alternative hypothesis (the claim), then using sample data to determine if the null can be rejected at a given significance level.
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Performing Hypothesis Tests: Proportions

Critical Value and Rejection Region

The critical value is a threshold that defines the boundary of the rejection region in hypothesis testing. It depends on the significance level (α) and the test type (one-tailed or two-tailed). If the test statistic falls into the rejection region beyond the critical value, the null hypothesis is rejected.
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Critical Values: t-Distribution

Two-Sample Z-Test for Means with Known Population Standard Deviations

This test compares the means of two independent samples when population standard deviations are known. It calculates a Z statistic based on sample means, population standard deviations, and sample sizes to assess if the difference between means is statistically significant.
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Population Standard Deviation Known
Related Practice
Textbook Question

Take this test as you would take a test in class.For each exercise, perform the steps below.

d. Find the appropriate standardized test statistic.


A real estate agency says that the mean home sales price in Olathe, Kansas, is greater than in Rolla, Missouri. The mean home sales price for 39 homes in Olathe is \$392,453. Assume the population standard deviation is \$224,902. The mean home sales price for 38 homes in Rolla is \$285,787. Assume the population standard deviation is \$330,578. At α=0.05, is there enough evidence to support the agency’s claim? (Adapted from Realtor.com)

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Textbook Question

In Exercises 4 and 5, use technology to perform a two-sample t-test to determine whether there is a difference in the mint dates and in the values of coins found on a street from 1985 through 1996 for the two mint locations. Write your conclusion as a sentence. Use α = 0.05.



Value of coins (dollars)


Philadelphia: x̅1=\(0.034, s1=\)0.054


Denver: x̅2=\(0.033, s2=\)0.052



Assume population variances are equal.

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Textbook Question

"In Exercises 17 and 18, (b) find the critical value(s) and identify the rejection region(s), Assume the samples are random and independent, and the populations are normally distributed.


A real estate agent claims that there is no difference between the mean household incomes of two neighborhoods. The mean income of 12 randomly selected households from the first neighborhood is \$52,750 with a standard deviation of \$2900. In the second neighborhood, 10 randomly selected households have a mean income of \$51,200 with a standard deviation of \$2225. At α=0.01, can you reject the real estate agent’s claim? Assume the population variances are equal."

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Textbook Question

In Exercises 11–16, test the claim about the difference between two population means μ1 and μ2 at the level of significance α. Assume the samples are random and independent, and the populations are normally distributed.


Claim: μ1= μ2; α=0.05. Assume (σ1)^2 = (σ2)^2


Sample statistics: x̅1=228, s1=27, n1= 20 and x̅2=207, s2=25, n2= 13

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Textbook Question

"Take this test as you would take a test in class.For each exercise, perform the steps below.

f. Interpret the decision in the context of the original claim.

A real estate agency says that the mean home sales price in Olathe, Kansas, is greater than in Rolla, Missouri. The mean home sales price for 39 homes in Olathe is \$392,453. Assume the population standard deviation is \$224,902. The mean home sales price for 38 homes in Rolla is \$285,787. Assume the population standard deviation is \$330,578. At α=0.05, is there enough evidence to support the agency’s claim? (Adapted from Realtor.com) "

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Textbook Question

Take this test as you would take a test in class.For each exercise, perform the steps below.

a. Identify the claim and state and


A real estate agency says that the mean home sales price in Olathe, Kansas, is greater than in Rolla, Missouri. The mean home sales price for 39 homes in Olathe is \$392,453. Assume the population standard deviation is \$224,902. The mean home sales price for 38 homes in Rolla is \$285,787. Assume the population standard deviation is \$330,578. At α=0.05, is there enough evidence to support the agency’s claim? (Adapted from Realtor.com)

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