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Ch. 8 - Hypothesis Testing with Two Samples
Larson - Elementary Statistics: Picturing the World 8th Edition
Larson8th EditionElementary Statistics: Picturing the WorldISBN: 9780137493470Not the one you use?Change textbook
Chapter 8, Problem 8.T.2a

Take this test as you would take a test in class.For each exercise, perform the steps below.

a. Identify the claim and state and


A real estate agency says that the mean home sales price in Olathe, Kansas, is greater than in Rolla, Missouri. The mean home sales price for 39 homes in Olathe is \$392,453. Assume the population standard deviation is \$224,902. The mean home sales price for 38 homes in Rolla is \$285,787. Assume the population standard deviation is \$330,578. At α=0.05, is there enough evidence to support the agency’s claim? (Adapted from Realtor.com)

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Step 1: Identify the claim and state the null hypothesis \(H_0\) and the alternative hypothesis \(H_a\). The claim is that the mean home sales price in Olathe is greater than in Rolla. So, let \(\mu_1\) be the mean price in Olathe and \(\mu_2\) be the mean price in Rolla. Then, the hypotheses are: \[ H_0: \mu_1 \leq \mu_2 \] \[ H_a: \mu_1 > \mu_2 \]
Step 2: Determine the significance level \(\alpha\), which is given as 0.05. This will be used to decide whether to reject the null hypothesis based on the test statistic.
Step 3: Since the population standard deviations are known, and the samples are independent, use the two-sample z-test for the difference of means. Calculate the test statistic using the formula: \[ z = \frac{(\bar{x}_1 - \bar{x}_2) - (\mu_1 - \mu_2)}{\sqrt{\frac{\sigma_1^2}{n_1} + \frac{\sigma_2^2}{n_2}}} \] Here, \(\bar{x}_1 = 392,453\), \(\bar{x}_2 = 285,787\), \(\sigma_1 = 224,902\), \(\sigma_2 = 330,578\), \(n_1 = 39\), and \(n_2 = 38\). Under the null hypothesis, \(\mu_1 - \mu_2 = 0\).
Step 4: Find the critical z-value for a right-tailed test at \(\alpha = 0.05\). This value corresponds to the z-score where the area to the right is 0.05.
Step 5: Compare the calculated test statistic to the critical z-value. If the test statistic is greater than the critical value, reject the null hypothesis and conclude there is enough evidence to support the claim. Otherwise, do not reject the null hypothesis.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Hypothesis Testing

Hypothesis testing is a statistical method used to decide whether there is enough evidence to support a specific claim about a population parameter. It involves formulating a null hypothesis (no effect or difference) and an alternative hypothesis (the claim), then using sample data to determine if the null can be rejected at a given significance level (α).
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Two-Sample Z-Test for Means

A two-sample z-test compares the means of two independent populations when population standard deviations are known. It calculates a z-score to measure the difference between sample means relative to the variability, helping determine if the observed difference is statistically significant under the null hypothesis.
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Significance Level and P-Value

The significance level (α) is the threshold for rejecting the null hypothesis, commonly set at 0.05. The p-value measures the probability of observing the sample data, or more extreme, assuming the null is true. If the p-value is less than α, the null hypothesis is rejected, supporting the alternative claim.
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Step 3: Get P-Value
Related Practice
Textbook Question

Take this test as you would take a test in class.For each exercise, perform the steps below.

d. Find the appropriate standardized test statistic.


A real estate agency says that the mean home sales price in Olathe, Kansas, is greater than in Rolla, Missouri. The mean home sales price for 39 homes in Olathe is \$392,453. Assume the population standard deviation is \$224,902. The mean home sales price for 38 homes in Rolla is \$285,787. Assume the population standard deviation is \$330,578. At α=0.05, is there enough evidence to support the agency’s claim? (Adapted from Realtor.com)

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Textbook Question

In Exercises 17 and 18, (c) find the standardized test statistic t, Assume the samples are random and independent, and the populations are normally distributed.


A real estate agent claims that there is no difference between the mean household incomes of two neighborhoods. The mean income of 12 randomly selected households from the first neighborhood is \$52,750 with a standard deviation of \$2900. In the second neighborhood, 10 randomly selected households have a mean income of \$51,200 with a standard deviation of \$2225. At α=0.01, can you reject the real estate agent’s claim? Assume the population variances are equal.

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Textbook Question

Take this test as you would take a test in class.For each exercise, perform the steps below.

c.Find the critical value(s) and identify the rejection region(s).



A real estate agency says that the mean home sales price in Olathe, Kansas, is greater than in Rolla, Missouri. The mean home sales price for 39 homes in Olathe is \$392,453. Assume the population standard deviation is \$224,902. The mean home sales price for 38 homes in Rolla is \$285,787. Assume the population standard deviation is \$330,578. At α=0.05, is there enough evidence to support the agency’s claim? (Adapted from Realtor.com)

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Textbook Question

"In Exercises 17 and 18, (b) find the critical value(s) and identify the rejection region(s), Assume the samples are random and independent, and the populations are normally distributed.


A real estate agent claims that there is no difference between the mean household incomes of two neighborhoods. The mean income of 12 randomly selected households from the first neighborhood is \$52,750 with a standard deviation of \$2900. In the second neighborhood, 10 randomly selected households have a mean income of \$51,200 with a standard deviation of \$2225. At α=0.01, can you reject the real estate agent’s claim? Assume the population variances are equal."

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Textbook Question

In Exercises 11–16, test the claim about the difference between two population means μ1 and μ2 at the level of significance α. Assume the samples are random and independent, and the populations are normally distributed.


Claim: μ1= μ2; α=0.05. Assume (σ1)^2 = (σ2)^2


Sample statistics: x̅1=228, s1=27, n1= 20 and x̅2=207, s2=25, n2= 13

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Textbook Question

"Take this test as you would take a test in class.For each exercise, perform the steps below.

f. Interpret the decision in the context of the original claim.

A real estate agency says that the mean home sales price in Olathe, Kansas, is greater than in Rolla, Missouri. The mean home sales price for 39 homes in Olathe is \$392,453. Assume the population standard deviation is \$224,902. The mean home sales price for 38 homes in Rolla is \$285,787. Assume the population standard deviation is \$330,578. At α=0.05, is there enough evidence to support the agency’s claim? (Adapted from Realtor.com) "

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