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Ch. 6 - Normal Probability Distributions
Triola - Elementary Statistics 14th Edition
Triola14th EditionElementary StatisticsISBN: 9780137366446Not the one you use?Change textbook
Chapter 6, Problem 7.CR.7b

Normal Distribution Using a larger data set than the one given for the preceding exercises, assume that cell phone radiation amounts are normally distributed with a mean of 1.17 W/kg and a standard deviation of 0.29 W/kg.
b. Find the value of Q3, the cell phone radiation amount that is the third quartile.

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1
Step 1: Understand the problem. The third quartile (Q3) in a normal distribution corresponds to the 75th percentile. This means we need to find the value of the random variable (cell phone radiation amount) such that 75% of the data lies below it.
Step 2: Recall the formula for standardizing a value in a normal distribution: z = (x - μ) / σ, where z is the z-score, x is the value of interest, μ is the mean, and σ is the standard deviation. Here, μ = 1.17 W/kg and σ = 0.29 W/kg.
Step 3: Use a z-score table or a statistical tool to find the z-score corresponding to the 75th percentile. From standard normal distribution tables, the z-score for the 75th percentile is approximately z = 0.674.
Step 4: Rearrange the z-score formula to solve for x (the value of Q3): x = z * σ + μ. Substitute the known values: z = 0.674, μ = 1.17, and σ = 0.29.
Step 5: Perform the calculation to find Q3. This will give you the cell phone radiation amount corresponding to the third quartile.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Normal Distribution

Normal distribution is a probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean. It is characterized by its bell-shaped curve, defined by its mean and standard deviation. In this context, the cell phone radiation amounts follow a normal distribution with a specified mean and standard deviation.
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Quartiles

Quartiles are values that divide a data set into four equal parts, each containing 25% of the data. The third quartile (Q3) is the value below which 75% of the data fall. It is a measure of statistical dispersion and helps in understanding the spread and central tendency of the data, particularly in a normal distribution.
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Calculating Q3 in Normal Distribution

To find Q3 in a normal distribution, one can use the z-score corresponding to the 75th percentile, which is approximately 0.674. The formula to calculate Q3 is Q3 = mean + (z-score * standard deviation). By substituting the given mean and standard deviation into this formula, one can determine the value of Q3 for the cell phone radiation amounts.
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Related Practice
Textbook Question

In Exercises 11–14, use the population of {2, 3, 5, 9} of the lengths of hospital stay (days) of mothers who gave birth, found from Data Set 6 “Births” in Appendix B. Assume that random samples of size n = 2 are selected with replacement.


Sampling Distribution of the Sample Mean


a. After identifying the 16 different possible samples, find the mean of each sample, and then construct a table representing the sampling distribution of the sample mean. In the table, combine values of the sample mean that are the same. (Hint: See Table 6-3 in Example 2.)

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Textbook Question

Bone Density Test A bone mineral density test is used to identify a bone disease. The result of a bone density test is commonly measured as a z score, and the population of z scores is normally distributed with a mean of 0 and a standard deviation of 1.


c. For a randomly selected subject, find the probability of a bone density test score between -0.67 and 1.29.

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Textbook Question

In Exercises 7–10, use the same population of {4, 5, 9} that was used in Examples 2 and 5. As in Examples 2 and 5, assume that samples of size n = 2 are randomly selected with replacement.


Sampling Distribution of the Sample Median


c. Find the mean of the sampling distribution of the sample median.

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Textbook Question

Bone Density Test A bone mineral density test is used to identify a bone disease. The result of a bone density test is commonly measured as a z score, and the population of z scores is normally distributed with a mean of 0 and a standard deviation of 1.


a. For a randomly selected subject, find the probability of a bone density test score greater than -1.37.

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Textbook Question

Quarters Assume that weights of quarters minted after 1964 are normally distributed with a mean of 5.670 g and a standard deviation of 0.062 g (based on U.S. Mint specifications).

a. Find the probability that a randomly selected quarter weighs between 5.600 g and 5.700 g..

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Textbook Question

Seat Designs. In Exercises 7–9, assume that when seated, adult males have back-to-knee lengths that are normally distributed with a mean of 23.5 in. and a standard deviation of 1.1 in. (based on anthropometric survey data from Gordon, Churchill, et al.). These data are used often in the design of different seats, including aircraft seats, train seats, theater seats, and classroom seats.


Find the probability that a male has a back-to-knee length greater than 25.0 in.

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