Skip to main content
Ch. 8 - Hypothesis Testing
Triola - Elementary Statistics 14th Edition
Triola14th EditionElementary StatisticsISBN: 9780137366446Not the one you use?Change textbook
Chapter 8, Problem 25

Large Data Sets from Appendix B
In Exercises 25–28, use the data set from Appendix B to test the given claim. Use the P-value method unless your instructor specifies otherwise.


Los Angeles Commute Time Use the 1000 Los Angeles Commute times listed in Data Set 31 “Commute Times” to test the claim that the mean Los Angeles commute time is less than 35 minutes. Use a 0.01 significance level. Compare the sample mean to the claimed mean of 35 minutes. Is the difference between those two values statistically significant? Does the difference between those two values appear to have practical significance?

Verified step by step guidance
1
Step 1: Define the null hypothesis (H₀) and the alternative hypothesis (H₁). The null hypothesis is H₀: μ = 35 (the mean commute time is 35 minutes), and the alternative hypothesis is H₁: μ < 35 (the mean commute time is less than 35 minutes). This is a left-tailed test.
Step 2: Identify the significance level (α). The problem specifies a significance level of 0.01, which means there is a 1% risk of rejecting the null hypothesis when it is true.
Step 3: Calculate the test statistic. Use the formula for the z-test for a population mean: z = (x̄ - μ) / (σ / √n), where x̄ is the sample mean, μ is the claimed population mean (35), σ is the population standard deviation (if known, or use the sample standard deviation if not), and n is the sample size (1000 in this case).
Step 4: Determine the P-value. Using the calculated z-test statistic, find the corresponding P-value from the standard normal distribution table. The P-value represents the probability of observing a test statistic as extreme as the one calculated, assuming the null hypothesis is true.
Step 5: Compare the P-value to the significance level (α). If the P-value is less than 0.01, reject the null hypothesis (H₀). If the P-value is greater than or equal to 0.01, fail to reject the null hypothesis. Then, assess practical significance by considering whether the difference between the sample mean and the claimed mean (35 minutes) is meaningful in the context of commute times.

Verified video answer for a similar problem:

This video solution was recommended by our tutors as helpful for the problem above.
Video duration:
4m
Was this helpful?

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Hypothesis Testing

Hypothesis testing is a statistical method used to make decisions about a population based on sample data. It involves formulating a null hypothesis (H0) and an alternative hypothesis (H1). In this case, the null hypothesis would state that the mean commute time is 35 minutes, while the alternative hypothesis would claim it is less than 35 minutes. The goal is to determine whether there is enough evidence to reject the null hypothesis at a specified significance level.
Recommended video:
Guided course
06:21
Step 1: Write Hypotheses

P-value

The P-value is a measure that helps determine the strength of the evidence against the null hypothesis. It represents the probability of obtaining a test statistic as extreme as, or more extreme than, the one observed, assuming the null hypothesis is true. A smaller P-value indicates stronger evidence against the null hypothesis. In this scenario, if the P-value is less than the significance level of 0.01, it suggests that the mean commute time is statistically significantly less than 35 minutes.
Recommended video:
Guided course
06:50
Step 3: Get P-Value

Statistical vs. Practical Significance

Statistical significance refers to the likelihood that a result or relationship is caused by something other than mere random chance, typically assessed through P-values. Practical significance, on the other hand, considers whether the size of the effect is large enough to be of real-world importance. In this context, even if the difference in commute times is statistically significant, it is essential to evaluate whether the difference is meaningful in practical terms, such as its impact on daily commuting experiences.
Recommended video:
Guided course
05:53
Parameters vs. Statistics
Related Practice
Textbook Question

Large Sample and a Small Difference It has been said that with really large samples, even very small differences between the sample mean and the claimed population mean can appear to be significant, but in reality they are not significant. Test this statement using the claim that the mean IQ score of adults is 100, given the following sample data: n = 1,000,000, x_bar = 100.05, s = 15 . Based on this sample, is the difference between x_bar = 100.05 and the claimed mean of 100 statistically significant? Does that difference have practical significance?

214
views
Textbook Question

Hypothesis Test with Known σ


a. How do the results from Example 1 in this section change if σ is known to be 1.99240984 g? Does the knowledge of σ have much of an effect on the results of this hypothesis test?

239
views
Textbook Question

Testing Hypotheses

In Exercises 13–24, assume that a simple random sample has been selected and test the given claim. Unless specified by your instructor, use either the P-value method or the critical value method for testing hypotheses. Identify the null and alternative hypotheses, test statistic, P-value (or range of P-values), or critical value(s), and state the final conclusion that addresses the original claim.


Got a Minute? Students of the author estimated the length of one minute without reference to a watch or clock, and the times (seconds) are listed below. Use a 0.05 significance level to test the claim that these times are from a population with a mean equal to 60 seconds. Does it appear that students are reasonably good at estimating one minute?


69 81 39 65 42 21 60 63 66 48 64 70 96 91 95

89
views
Textbook Question

Testing Hypotheses

In Exercises 13–24, assume that a simple random sample has been selected and test the given claim. Unless specified by your instructor, use either the P-value method or the critical value method for testing hypotheses. Identify the null and alternative hypotheses, test statistic, P-value (or range of P-values), or critical value(s), and state the final conclusion that addresses the original claim.


Is the Diet Practical? When 40 people used the Weight Watchers diet for one year, their mean weight loss was 3.0 lb and the standard deviation was 4.9 lb (based on data from “Comparison of the Atkins, Ornish, Weight Watchers, and Zone Diets for Weight Loss and Heart Disease Reduction,” by Dansinger et al., Journal of the American Medical Association, Vol. 293, No. 1). Use a 0.01 significance level to test the claim that the mean weight loss is greater than 0. Based on these results, does the diet appear to have statistical significance? Does the diet appear to have practical significance?

224
views
Textbook Question

Testing Hypotheses

In Exercises 13–24, assume that a simple random sample has been selected and test the given claim. Unless specified by your instructor, use either the P-value method or the critical value method for testing hypotheses. Identify the null and alternative hypotheses, test statistic, P-value (or range of P-values), or critical value(s), and state the final conclusion that addresses the original claim.


Lead in Medicine Listed below are the lead concentrations (in ) measured in different Ayurveda medicines. Ayurveda is a traditional medical system commonly used in India. The lead concentrations listed here are from medicines manufactured in the United States (based on data from “Lead, Mercury, and Arsenic in US and Indian Manufactured Ayurvedic Medicines Sold via the Internet,” by Saper et al., Journal of the American Medical Association, Vol. 300, No. 8). Use a 0.05 significance level to test the claim that the mean lead concentration for all such medicines is less than 14 μg/g.


3.0 6.5 6.0 5.5 20.5 7.5 12 20.5 11.5 17.5

91
views