In Exercises 39–48, factor the difference of two squares. 36x^2−4...

Question

In Exercises 39–48, factor the difference of two squares. 36x^2−49y^2

Accepted Answer

Hello. Today we're going to be factoring a given expression. So the expression given to us is 49 x squared -121. Now, if you take a look at the first term in last term here, both of these terms are perfect squares. 49 X squared can be rewritten as seven X raised to the power of two and 121 can be rewritten as 11 squared. So what we have here is a difference of square terms and we do have a special factory ization for that. When we have the quantity A squared minus B squared. This can be factored to two quantities A plus B times a minus B. So in order to use this, we need to go ahead and identify what are A and B are. Well A is just going to be the factor of the first term which is going to be seven X. So A is equal to seven X and B is the factor of the second term. So B is going to equal to 11. Now what we want to do is go ahead and plug in these values of A and B into our factory Ization doing so is going to give me a plus B which is seven X plus 11 times a minus B, which is seven x minus 11. And this is going to be the complete factory ization of our given polynomial. And that means that the answer to this problem is going to be be So I hope this video helps you in understanding how to factor a different sub squares, and I'll go ahead and see you all in the next video.

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