Hey everyone where asked which of the following is the correct name for the alkaline first. Let's go ahead and determine our route chain, which can also be called our parent chain. And this means it is our longest chain. So counting off we have and nine. It looks like we have a nine carbon chain. But let's go ahead and count it off going to the right straight away. So we have and eight. So we can see that this red numbering gives us only eight carbons. So this can't be our answer. So we can safely eliminate D. Since D tells us that our longest chain is an eight carbon chain due to that prefix of oct. Now why don't we number this in the reverse way? So Why didn't we remember this as 12345678 and nine. So the numbering in red would be incorrect. And the reason why is because Our al Qaeda here is listed at carbon # six. And we want our al Qaeda to have the lowest number possible since it takes priority. And with our blue lettering are al kind is written at carbon # three. And since we've recognized that carbon number three, we can also eliminate answer choice A. Since it tells us that our al Qaeda's at carbon number two. Now to look at our substitute wint, we can see that our substitution is at carbon # six and I'll go ahead and highlight it in pink. Now this is our substitute wint and we can see that we have a beautiful group so we can go ahead and eliminate answer choice B. Since this tells us that we have three different substitue ints and looking at carbon number six, we don't have an ethyl group and looking at carbon number seven, we do not have a dimethyl group. So our answer here is going to be C six Tribunal three non nine. Now, I hope that made sense and let us know if you have any questions.

Ch.21 - Organic Chemistry

Tro - Chemistry: A Molecular Approach 4th Edition

Tro4th EditionChemistry: A Molecular ApproachISBN: 9780134112831Not the one you use?Change textbook

All textbooks

Tro 4th Edition

Ch.21 - Organic Chemistry

Problem 54d

Chapter 21, Problem 54d

Name each alkyne. d.

Verified step by step guidance

Step 1: Identify the longest carbon chain that includes the triple bond. This will determine the base name of the alkyne.

Step 2: Number the carbon chain starting from the end nearest to the triple bond to give the lowest possible number to the triple bond.

Step 3: Identify and name any substituents attached to the main carbon chain.

Step 4: Combine the names of the substituents with the base name of the alkyne, placing the substituents in alphabetical order and using numbers to indicate their positions.

Step 5: Ensure the name follows IUPAC nomenclature rules, including the use of hyphens and commas as needed.

Verified video answer for a similar problem:

This video solution was recommended by our tutors as helpful for the problem above.

Video duration:

Was this helpful?

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Alkynes

Alkynes are a class of hydrocarbons characterized by at least one carbon-carbon triple bond (C≡C). They follow the general formula CnH2n-2, where 'n' is the number of carbon atoms. Alkynes are unsaturated compounds, meaning they contain fewer hydrogen atoms than alkanes and alkenes, which can affect their reactivity and physical properties.

Nomenclature of Alkynes

The nomenclature of alkynes follows the IUPAC (International Union of Pure and Applied Chemistry) rules, which involve identifying the longest carbon chain containing the triple bond. The name is derived from the number of carbon atoms in the chain, with the suffix '-yne' indicating the presence of a triple bond. For example, a three-carbon alkyne is named propyne.

Isomerism in Alkynes

Alkynes can exhibit structural isomerism, where compounds with the same molecular formula have different arrangements of atoms. This includes positional isomerism, where the location of the triple bond varies within the carbon chain. Understanding isomerism is crucial for naming and distinguishing between different alkynes, as it can lead to different chemical properties and reactivities.