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Ch. 4 - Gene Interaction
Sanders - Genetic Analysis: An Integrated Approach 3rd Edition
Sanders3rd EditionGenetic Analysis: An Integrated ApproachISBN: 9780135564172Not the one you use?Change textbook
Chapter 4, Problem 28a

Yeast are single-celled eukaryotic organisms that grow in culture as either haploids or diploids. Diploid yeast are generated when two haploid strains fuse together. Seven haploid mutant strains of yeast exhibit similar normal growth habit at 25°C, but at 37°C, they show different growth capabilities. The table below displays the growth pattern.
Table showing yeast strain growth at 25°C and 37°C, indicating normal, slow, and no growth for each strain.
Hypothesize about the nature of the mutation affecting each of these mutant yeast strains, including why strains B and G display different growth habit at 37°C than the other strains.

Verified step by step guidance
1
Understand the problem: The question involves analyzing the growth patterns of mutant yeast strains at different temperatures (25°C and 37°C). The goal is to hypothesize the nature of the mutations and explain why strains B and G behave differently at 37°C compared to the others.
Step 1: Recall that yeast can exist as haploid or diploid cells. Mutations in haploid yeast strains can directly affect their phenotype because there is no second allele to mask the mutation. This means that any mutation affecting growth at 37°C is likely due to a single defective gene in each strain.
Step 2: Analyze the growth patterns at 25°C and 37°C. Since all strains grow normally at 25°C, the mutations likely affect temperature-sensitive genes. These genes may encode proteins that are functional at lower temperatures but become misfolded or non-functional at higher temperatures (37°C).
Step 3: Hypothesize the nature of the mutations. For strains B and G, their different growth habits at 37°C suggest that the mutations in these strains may affect different pathways or genes compared to the other strains. For example, strain B might have a mutation in a gene involved in heat shock response, while strain G might have a mutation in a gene critical for cell division at higher temperatures.
Step 4: Consider genetic interactions. If strains B and G display unique growth patterns, it is possible that their mutations are in genes that interact with other cellular pathways differently than the mutations in the other strains. This could explain their distinct behavior at 37°C.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Haploidy and Diploidy

Haploidy refers to cells that contain a single set of chromosomes, while diploidy indicates cells with two sets. In yeast, haploid strains can mate to form diploid cells, which can undergo meiosis to produce haploid spores. Understanding the difference between these two states is crucial for analyzing genetic mutations and their effects on growth under varying conditions.
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Diploid Genetics

Temperature Sensitivity in Mutants

Temperature sensitivity in mutant strains refers to the phenomenon where certain mutations affect the organism's ability to grow or function at specific temperatures. In this case, the yeast strains exhibit normal growth at 25°C but show varied growth capabilities at 37°C, suggesting that the mutations may impact protein stability or enzymatic activity at higher temperatures.
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Mutations and Phenotypes

Genetic Mutations and Phenotypic Expression

Genetic mutations are changes in the DNA sequence that can lead to alterations in an organism's phenotype, or observable traits. The differences in growth habits of strains B and G at 37°C compared to other strains may indicate specific mutations that affect metabolic pathways or stress responses, highlighting the relationship between genotype and phenotype in response to environmental changes.
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Related Practice
Textbook Question

Two pure-breeding strains of summer squash producing yellow fruit, Y₁ and Y₂, are each crossed to a pure-breeding strain of summer squash producing green fruit, G₁, and to one another. The following results are obtained:

Using clearly defined symbols of your choice, give the genotypes of parental, F₁, and F₂ plants in each cross. 

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Textbook Question

Two pure-breeding strains of summer squash producing yellow fruit, Y₁ and Y₂, are each crossed to a pure-breeding strain of summer squash producing green fruit, G₁, and to one another. The following results are obtained:

If the F₁ of Crosses I and II are mated, predict the phenotype ratio of the progeny. 

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Textbook Question

Marfan syndrome is an autosomal dominant disorder in humans. It results from mutation of a gene on chromosome 15 that produces the connective tissue protein fibrillin. In its wild-type form, fibrillin gives connective tissues, such as cartilage, elasticity. When mutated, however, fibrillin is rigid and produces a range of phenotypic complications, including excessive growth of the long bones of the leg and arm, sunken chest, dislocation of the lens of the eye, and susceptibility to aortic aneurysm, which can lead to sudden death in some cases. Different sets of symptoms are seen among various family members, as shown in the pedigree below. Each quadrant of the circles and squares represents a different symptom, as the key indicates.

All cases of Marfan syndrome are caused by mutation of the fibrillin gene, and all family members with Marfan syndrome carry the same mutant allele. What do the differences shown in the phenotypes of family members say about the expression of the mutant allele?

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Textbook Question

Yeast are single-celled eukaryotic organisms that grow in culture as either haploids or diploids. Diploid yeast are generated when two haploid strains fuse together. Seven haploid mutant strains of yeast exhibit similar normal growth habit at 25°C, but at 37°C, they show different growth capabilities. The table below displays the growth pattern.

Researchers induce fusion in pairs of haploid yeast strains (all possible combinations), and the resulting diploids are tested for their ability to grow at 37°C. The results of the growth experiment are shown below. How many different genes are mutated among these seven yeast strains? Identify the strains that represent each gene mutation.

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Textbook Question

Dr. Ara B. Dopsis and Dr. C. Ellie Gans are performing genetic crosses on daisy plants. They self-fertilize a blue-flowered daisy and grow 100 progeny plants that consist of 55 blue-flowered plants, 22 purple-flowered plants, and 23 white-flowered plants. Dr. Dopsis believes this is the result of segregation of two alleles at one locus and that the progeny ratio is 1:2:1. Dr. Gans thinks the progeny phenotypes are the result of two epistatic genes and that the ratio is 9:3:4.

The two scientists ask you to resolve their conflict by performing chi-square analysis on the data for both proposed genetic mechanisms. For each proposed mechanism, fill in the values requested on the form the researchers have provided for your analysis.

Use the form below to calculate chi-square for the 1:2:1 hypothesis of Dr. Sophila.

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Textbook Question

Dr. Ara B. Dopsis and Dr. C. Ellie Gans are performing genetic crosses on daisy plants. They self-fertilize a blue-flowered daisy and grow 100 progeny plants that consist of 55 blue-flowered plants, 22 purple-flowered plants, and 23 white-flowered plants. Dr. Dopsis believes this is the result of segregation of two alleles at one locus and that the progeny ratio is 1:2:1. Dr. Gans thinks the progeny phenotypes are the result of two epistatic genes and that the ratio is 9:3:4.

The two scientists ask you to resolve their conflict by performing chi-square analysis on the data for both proposed genetic mechanisms. For each proposed mechanism, fill in the values requested on the form the researchers have provided for your analysis.

Use the form below to calculate chi-square for the 9:3:4 hypothesis of Dr. Gans.

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