Determine if each of the following cycloalkanes or alkenes can exist as cis–trans stereoisomers. For those that can, draw the two isomers. Label each of the isomers you drew as the cis stereoisomer or the trans stereoisomer.
(b) CH₃CH₂CH₂CH₂CH=CH₂

Question

Determine if each of the following cycloalkanes or alkenes can exist as cis–trans stereoisomers. For those that can, draw the two isomers. Label each of the isomers you drew as the cis stereoisomer or the trans stereoisomer.
(b) CH₃CH₂CH₂CH₂CH=CH₂

(b) CH₃CH₂CH₂CH₂CH=CH₂

Accepted Answer

Welcome back everyone. For the following L Kane determine whether it can exhibit cyst trans thee isomerism if it can draw the correct cyst in transforms. And we're given C bromo T beating. So if we want to draw the structure, we're going to begin with the parent, which is be and basically, we know that butane represents a four member carbon chain. So we have 123 and four carbons. Now, if we label the carbon atoms given to us, we noticed that carbon number two contains a bromo substituent and a double bond because it's two but 10, so that two represents the position of the double bond. And we simply want to extend a pi bond between carbons two and three because two but 10 states where the double bond begins and we basically extend it to the next carbon atoms in the structure. Carbon number two also contains a bromo substituent, which is simply br so we have drawn the structure of the L king. We don't know if it can exhibit stereoisomerism, but we are going to determine that whenever NL Kane can have cis trans isomerism, we want to make sure that first of all, all of the double bonded carbon atoms. In this case, carbons two and three, they must have different substitutions. So let's say carbon number two contains a bromo substituent in the methyl group. And those are different carbon. Number three, it has a methyl substituent and it has an implicit hydrogen atom and those are different, right? Which means that yes, this structure can exhibit cran isomerism also because we have two alkyl groups on carbons two and three. And essentially what we want to do is simply identify how those alki groups are distributed in relation to each other. Now, specifically for this problem, we want to identify the priorities of the groups starting with carbon. Number one, we're comparing carbon versus bromine and bromine gets a higher priority than carbon because it has a higher atomic number for carbon. Number three, we are comparing hygen versus carbon and carbon gets a high priority due to the same reason, it has a higher atomic number than hygen. Since the highest priority groups are on the same side of the double bond. This is simply a sis arrangement. So we can now confidently draw this form of the given a king, a four member chain, a double bond between carbons two and three. And we want to make sure that the bromo substituent is on the same side as the metal group. There is no necessity to show the implicit hygiene at all. So that'll be the cis form for the transform, we actually want to make sure that the highest priority groups are now on opposite sides of the double bond. So we can simply change the position of that muscle group and we can just draw it downwards instead of winding up. So now the promo substituent is on the opposite side of the double B relative to the metal group, right? They are on opposite sides if we just draw a vertical line and that means we have our trans isomer and those would be the final answers to this problem. Thank you for watching.

Determine if each of the following cycloalkanes or alkenes can exist as cis–trans stereoisomers. For those that can, draw the two isomers. Label each of the isomers you drew as the cis stereoisomer or the trans stereoisomer.
(b) CH₃CH₂CH₂CH₂CH=CH₂

Verified video answer for a similar problem:

Key Concepts

Cis-Trans Isomerism

Cycloalkanes and Alkenes

Drawing Isomers

Determine if each of the following cycloalkanes or alkenes can exist as cis–trans stereoisomers. For those that can, draw the two isomers. Label each of the isomers you drew as the cis stereoisomer or the trans stereoisomer.(b) CH3CH2CH2CH2CH=CH2

Verified video answer for a similar problem:

Key Concepts

Cis-Trans Isomerism

Cycloalkanes and Alkenes

Drawing Isomers

Determine if each of the following cycloalkanes or alkenes can exist as cis–trans stereoisomers. For those that can, draw the two isomers. Label each of the isomers you drew as the cis stereoisomer or the trans stereoisomer.
(b) CH₃CH₂CH₂CH₂CH=CH₂