Are the α and β forms of the disaccharide lactose enantiomers of each other? Why or why not?
Ch.20 Carbohydrates
McMurry8th EditionFundamentals of General, Organic, and Biological ChemistryISBN: 9780134015187당신이 사용하는 게 아니라요?교과서 변경
20장, 문제 76
D-Fructose can form a six-membered cyclic hemiacetal as well as the more prevalent five-membered cyclic form. Draw the α isomer of D-fructose in the six-membered ring.
검증된 단계별 안내1
Understand that d-fructose is a ketohexose, meaning it contains six carbons and a ketone functional group. The cyclic forms are created when the ketone group reacts with a hydroxyl group on the molecule to form a hemiacetal.
Identify the six-membered cyclic form of d-fructose. This is called a pyranose form, where the ketone group on carbon 2 reacts with the hydroxyl group on carbon 6 to form a six-membered ring.
Draw the six-membered ring structure. Place oxygen as one of the ring members and arrange the remaining carbons (C2 through C6) and their substituents around the ring. Ensure the ring closure occurs between C2 and C6.
Determine the α isomer. In the α isomer, the hydroxyl group attached to the anomeric carbon (C2 in this case) is positioned *down* (opposite to the CH2OH group attached to C5) in the Haworth projection.
Complete the structure by adding the remaining hydroxyl groups and hydrogen atoms to the appropriate carbons, ensuring the stereochemistry matches that of d-fructose. Verify that the configuration of the chiral centers (C3, C4, and C5) corresponds to the d-fructose configuration.

비슷한 문제에 대한 검증된 영상 답변:
이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
영상 길이:
8m도움이 되었나요?
주요 개념
질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.
Cyclic Hemiacetal Formation
Cyclic hemiacetals are formed when a carbonyl group (aldehyde or ketone) reacts with an alcohol, resulting in a ring structure. In the case of d-fructose, the ketone group at C2 reacts with the hydroxyl group on C5, leading to the formation of a six-membered ring. This reaction is crucial for understanding the structural variations of sugars.
추천 영상:
가이드 코스
Cyclic Hemiacetals Concept 2
Anomeric Carbon
The anomeric carbon is the carbon atom in a sugar that was originally part of the carbonyl group and becomes a new chiral center upon cyclization. In d-fructose, the anomeric carbon is C2 in the six-membered ring. The configuration at this carbon determines whether the sugar is in the α or β form, which is essential for distinguishing between different isomers.
추천 영상:
가이드 코스
Amino Acid Catabolism: Carbon Atoms Concept 2
Furanose vs. Pyranose Forms
Sugars can exist in different cyclic forms, primarily furanose (five-membered) and pyranose (six-membered) rings. d-Fructose predominantly exists as a furanose, but it can also form a pyranose structure. Understanding these forms is important for grasping the reactivity and biological roles of sugars in various biochemical processes.
추천 영상:
가이드 코스
Periodic Table: Elemental Forms (Simplified) Concept 1
관련 실천
교과서 질문
1005
views
교과서 질문
Describe the differences between mono-, di-, and polysaccharides.
1622
views
교과서 질문
Trehalose, a disaccharide found in the blood of insects, has the following structure. What simple sugars would you obtain on hydrolysis of trehalose? (Hint: Rotate one of the rings in your head or redraw it rotated.)
1117
views
교과서 질문
Carbohydrates provide 4 kcal per gram. If a person eats 200 g per day of digestible carbohydrates, what percentage of a 2000 kcal daily diet would be digestible carbohydrate?
746
views
교과서 질문
How are amylose and amylopectin similar to each other, and how are they different from each other?
595
views
교과서 질문
Name a naturally occurring carbohydrate and its source for each type of carbohydrate listed in Problem 20.83.
666
views
