Skip to main content
Ch. 11 - Power Series
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Not the one you use?Change textbook
Chapter 11, Problem 11.2.61

Functions to power series Find power series representations centered at 0 for the following functions using known power series. Give the interval of convergence for the resulting series.
f(x) = ln √(4 − x²)

Verified step by step guidance
1
Rewrite the function to a more convenient form: \( f(x) = \ln \sqrt{4 - x^2} = \frac{1}{2} \ln(4 - x^2) \). This simplifies the problem to finding the power series for \( \ln(4 - x^2) \).
Express \( \ln(4 - x^2) \) in terms of \( \ln 4 \) and a logarithm of a form suitable for a known power series: \( \ln(4 - x^2) = \ln 4 + \ln\left(1 - \frac{x^2}{4}\right) \).
Recall the known power series for \( \ln(1 - u) = -\sum_{n=1}^\infty \frac{u^n}{n} \) valid for \( |u| < 1 \). Here, set \( u = \frac{x^2}{4} \).
Substitute \( u = \frac{x^2}{4} \) into the series to get \( \ln\left(1 - \frac{x^2}{4}\right) = -\sum_{n=1}^\infty \frac{1}{n} \left(\frac{x^2}{4}\right)^n = -\sum_{n=1}^\infty \frac{x^{2n}}{n 4^n} \).
Combine all parts to write the power series for \( f(x) \): \( f(x) = \frac{1}{2} \ln 4 - \frac{1}{2} \sum_{n=1}^\infty \frac{x^{2n}}{n 4^n} \). The interval of convergence comes from \( |u| = \left|\frac{x^2}{4}\right| < 1 \), which simplifies to \( |x| < 2 \).

Verified video answer for a similar problem:

This video solution was recommended by our tutors as helpful for the problem above.
Video duration:
5m
Was this helpful?

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Power Series Representation

A power series is an infinite sum of terms in the form a_n(x - c)^n, where c is the center of the series. Representing functions as power series allows approximation and analysis using polynomials. Finding a power series for a function often involves manipulating known series or using derivatives and integrals.
Recommended video:
05:58
Intro to Power Series

Known Power Series and Manipulation

Common functions like ln(1+x), 1/(1-x), and sqrt(1-x) have established power series expansions. To find the series for a related function, express it in terms of these known forms and apply algebraic operations, substitutions, or differentiation/integration to derive the new series.
Recommended video:
05:58
Intro to Power Series

Interval of Convergence

The interval of convergence is the set of x-values for which the power series converges to the function. It depends on the radius of convergence, often found using the ratio or root test. Determining this interval is crucial to ensure the series accurately represents the function within that domain.
Recommended video:
08:44
Interval of Convergence