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Ch. 10 - Sequences and Infinite Series
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Not the one you use?Change textbook
Chapter 10, Problem 10.8.55

11–86. Applying convergence tests Determine whether the following series converge. Justify your answers.
∑ (from k = 1 to ∞)cos(1 / k⁹)

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First, write down the general term of the series: \(a_k = \cos\left(\frac{1}{k^9}\right)\).
Recall that for a series \(\sum a_k\) to converge, the terms \(a_k\) must approach zero as \(k\) approaches infinity. So, evaluate \(\lim_{k \to \infty} a_k = \lim_{k \to \infty} \cos\left(\frac{1}{k^9}\right)\).
Since \(\frac{1}{k^9} \to 0\) as \(k \to \infty\), use the continuity of cosine to find \(\lim_{k \to \infty} \cos\left(\frac{1}{k^9}\right) = \cos(0) = 1\).
Because the terms \(a_k\) do not approach zero (they approach 1), the necessary condition for convergence of the series is not met. Therefore, the series \(\sum_{k=1}^\infty \cos\left(\frac{1}{k^9}\right)\) diverges.
In conclusion, no further convergence tests are needed since the terms do not tend to zero, and the series diverges by the Test for Divergence (also called the nth-term test).

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Key Concepts

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