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Ch. 7 - Logarithmic, Exponential Functions, and Hyperbolic Functions
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Not the one you use?Change textbook
Chapter 7, Problem 7.1.51

29–62. Integrals Evaluate the following integrals. Include absolute values only when needed.


∫ 3^{-2x} dx

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1
Recognize that the integral involves an exponential function with base 3 and exponent \(-2x\). The integral is \(\int 3^{-2x} \, dx\).
Rewrite the integrand using the exponential function with base \(e\): \(3^{-2x} = e^{\ln(3^{-2x})} = e^{-2x \ln(3)}\).
Set \(a = -2 \ln(3)\) to simplify the expression, so the integral becomes \(\int e^{ax} \, dx\).
Recall the formula for integrating an exponential function: \(\int e^{ax} \, dx = \frac{1}{a} e^{ax} + C\), where \(C\) is the constant of integration.
Substitute back \(a = -2 \ln(3)\) and rewrite the answer in terms of the original base 3 exponential function to express the integral result.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Integration of Exponential Functions

Integrating exponential functions involves finding the antiderivative of expressions where the variable is in the exponent. For functions like a^x, the integral is (a^x) / (ln a) plus a constant, provided a > 0 and a ≠ 1.
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Integrals of General Exponential Functions

Properties of Logarithms

Logarithms, especially natural logs (ln), are essential when integrating exponential functions with bases other than e. Understanding that ln(a) is the natural logarithm of the base a helps in applying the integration formula correctly.
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Change of Base Property

Handling Negative Exponents

Negative exponents represent reciprocal powers, such as a^{-x} = 1 / a^x. Recognizing this helps in rewriting the integral or applying substitution methods to simplify the integration process.
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Zero and Negative Rules
Related Practice
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Express sinh⁻¹ x in terms of logarithms.

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22–36. Derivatives Find the derivatives of the following functions.


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Haitz’s law predicts that the cost per lumen of an LED bulb decreases by a factor of 10 every 10 years. This means that 10 years from now, the cost of an LED bulb will be 1/10 of its current cost. Predict the cost of a particular LED bulb in 2021 if it costs 4 dollars in 2018.

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Textbook Question

13–14. Absolute and relative growth rates Two functions f and g are given. Show that the growth rate of the linear function is constant and the relative growth rate of the exponential function is constant.


f(t) = 100 + 10.5t, g(t) = 100e^(t/10)

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