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Ch. 7 - Transcendental Functions
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Not the one you use?Change textbook
Chapter 7, Problem 7.6.96

Evaluate the integrals in Exercises 91–102.
96. ∫dy/((arcsin y)(1-y²))

Verified step by step guidance
1
Recognize that the integral is of the form \(\int \frac{dy}{(\arcsin y)(1 - y^2)}\). Notice that the denominator contains \(1 - y^2\), which is related to the derivative of \(\arcsin y\).
Recall the derivative formula: \(\frac{d}{dy}(\arcsin y) = \frac{1}{\sqrt{1 - y^2}}\). This suggests a substitution involving \(\arcsin y\) might simplify the integral.
Let \(t = \arcsin y\). Then, differentiate both sides to find \(dy\) in terms of \(dt\): \(dy = \cos t \, dt\), since \(y = \sin t\) and \(dy/dt = \cos t\).
Rewrite the integral in terms of \(t\): substitute \(y = \sin t\) and \(dy = \cos t \, dt\). Also, express \(1 - y^2\) as \(1 - \sin^2 t = \cos^2 t\). The integral becomes \(\int \frac{\cos t \, dt}{t \cdot \cos^2 t} = \int \frac{dt}{t \cdot \cos t}\).
Now, the integral is \(\int \frac{dt}{t \cos t}\). From here, consider methods such as integration by parts or special functions to proceed, depending on the context or allowed techniques.

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Key Concepts

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