Use the structure of D-galactose in Problem 6.15 to answer the following:
(a) Draw the Fischer projection of the carbon 3 epimer.

Question

Use the structure of D-galactose in Problem 6.15 to answer the following:

Fischer projections of D-galactose and its carbon 3 epimer variations labeled A, B, and C.

(a) Draw the Fischer projection of the carbon 3 epimer.

Accepted Answer

Welcome back everyone to the fissure projection of the C three of the glucose. In this problem, we're given the structure of the glucose. We want to draw its carbon three omer. And we have to recall that an omer is simply a ditherer of a specific structure in which we are only changing the configuration of one and only one chiral carbon atom. So in this problem, we're going to label our carbons, we have 12345 and six carbons specifically looking at carbon number three, this is the carbon atom at which we are going to reverse the configuration. So first of all, let's redraw whatever we have starting with cho and L the hype for carbon number two, hydrogen on the left hydroxyl on the right, nothing changes for carbon. Number three. If we want to reverse the configuration and get an er then we simply want to swap hydrogen with hydroxyl such that hydrogen is now on the left side and not on the right hydroxyl is now on the right. And now for the remaining carbons, carbon number four, nothing changes. Carbon number five, nothing changes again. So we have all of the hydroxyl groups on the left followed by the A chiral position ch 20. And that would be the required carbon three , of the glucose. Thank you for watching.

Use the structure of D-galactose in Problem 6.15 to answer the following:

(a) Draw the Fischer projection of the carbon 3 epimer.

Verified video answer for a similar problem:

Key Concepts

Fischer Projection

Epimers

D-Galactose Structure