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Ch.6 Chemical Reactions: Mole and Mass Relationships
McMurry - Fundamentals of GOB 8th Edition
McMurry8th EditionFundamentals of GOBISBN: 9780134015187Not the one you use?Change textbook
Chapter 6, Problem 43b

Titanium metal is obtained from the mineral rutile, TiO2. The process requires multiple steps, as shown in the following reactions:
TiO2(s) + 2 Cl2(g) + 2 C(s) → TiCl4(s) + 2 CO(g)
TiCl4(s) + 2 Mg(s) → Ti(s) + 2 MgCl2(s)
b. How many moles of TiO2 are needed to form one mole of titanium?

Verified step by step guidance
1
Step 1: Analyze the problem and identify the goal. The goal is to determine how many moles of TiO2 are required to produce 1 mole of titanium (Ti). This involves understanding the stoichiometry of the reactions provided.
Step 2: Examine the first reaction: TiO2(s) + 2 Cl2(g) + 2 C(s) → TiCl4(s) + 2 CO(g). From this reaction, 1 mole of TiO2 reacts to produce 1 mole of TiCl4. This establishes a 1:1 molar ratio between TiO2 and TiCl4.
Step 3: Examine the second reaction: TiCl4(s) + 2 Mg(s) → Ti(s) + 2 MgCl2(s). From this reaction, 1 mole of TiCl4 reacts to produce 1 mole of Ti. This establishes a 1:1 molar ratio between TiCl4 and Ti.
Step 4: Combine the stoichiometric relationships from both reactions. Since 1 mole of TiO2 produces 1 mole of TiCl4 (from the first reaction), and 1 mole of TiCl4 produces 1 mole of Ti (from the second reaction), the overall stoichiometry shows that 1 mole of TiO2 is required to produce 1 mole of Ti.
Step 5: Conclude that the number of moles of TiO2 needed to form 1 mole of titanium is 1 mole, based on the stoichiometric relationships in the given reactions.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Stoichiometry

Stoichiometry is the branch of chemistry that deals with the quantitative relationships between the reactants and products in a chemical reaction. It allows us to calculate the amounts of substances involved based on balanced chemical equations. Understanding stoichiometry is essential for determining how many moles of a reactant are needed to produce a desired amount of product.
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Stoichiometry

Mole Concept

The mole concept is a fundamental principle in chemistry that defines the amount of substance. One mole is equivalent to 6.022 x 10^23 entities (atoms, molecules, etc.). This concept is crucial for converting between grams and moles, enabling chemists to quantify reactants and products in chemical reactions accurately.
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Chemical Reactions and Balancing

Chemical reactions involve the transformation of reactants into products, and balancing these reactions ensures that the law of conservation of mass is upheld. Each side of a balanced equation must have the same number of atoms for each element. In the given reactions, balancing is necessary to determine the exact mole ratios between TiO2 and titanium, which is vital for solving the problem.
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Related Practice
Textbook Question

Caffeine has the formula C8H10N4O2. If an average cup of coffee contains approximately 125 mg of caffeine, how many moles of caffeine are in one cup?

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Textbook Question

The principal component of many kidney stones is calcium oxalate, CaC2O4. A kidney stone recovered from a typical patient contains 8.5 × 1020 formula units of calcium oxalate. How many moles of CaC2O4 are present in this kidney stone? What is the mass of the kidney stone in grams?

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Textbook Question

Titanium metal is obtained from the mineral rutile, TiO2. The process requires multiple steps, as shown in the following reactions:

TiO2(s) + 2 Cl2(g) + 2 C(s) → TiCl4(s) + 2 CO(g)

TiCl4(s) + 2 Mg(s) → Ti(s) + 2 MgCl2(s)

a. Write mole ratios to show the relationship between the reactants and products for each reaction.

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views
Textbook Question

Titanium metal is obtained from the mineral rutile, TiO2. The process requires multiple steps, as shown in the following reactions:

TiO2(s) + 2 Cl2(g) + 2 C(s) → TiCl4(s) + 2 CO(g)

TiCl4(s) + 2 Mg(s) → Ti(s) + 2 MgCl2(s)

c. How many kilograms of rutile are needed to produce 95 kg of Ti?

1552
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Textbook Question

In Problem 6.40, hydrazine reacted with oxygen according to the following (unbalanced) equation: N2H4(l) + O2(g) → NO2(g) + H2O(g)

a. If 75.0 kg of hydrazine are reacted with 75.0 kg of oxygen, which is the limiting reagent?

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Textbook Question

Nitrobenzene (C6H5NO2) is used in small quantities as a flavoring agent or in perfumes but can be toxic in large amounts. It is produced by reaction of benzene (C6H6) with nitric acid:

C6H6(l) + HNO3(aq) → C6H5NO2(l) + H2O(l)

a. Identify the limiting reagent in the reaction of 27.5 g of nitric acid with 75 g of benzene.

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