Uric acid, the principal constituent of some kidney stones, has the formula C5H4N4O3. In aqueous solution, the solubility of uric acid is only 0.067 g/L. Express this concentration in (m/v)%, in parts per million, and in molarity.
Ch.9 Solutions
McMurry8th EditionFundamentals of General, Organic, and Biological ChemistryISBN: 9780134015187당신이 사용하는 게 아니라요?교과서 변경
9장, 문제 81b
Which of the following solutions has the higher osmolarity?
b. 0.30 M NaOH or 3.0% (m/v) NaOH
검증된 단계별 안내1
Step 1: Understand the concept of osmolarity. Osmolarity is the total concentration of all solute particles in a solution. For ionic compounds like NaOH, it dissociates into ions in water. Each mole of NaOH dissociates into one mole of Na⁺ and one mole of OH⁻, contributing two particles to the osmolarity.
Step 2: Calculate the osmolarity of the 0.30 M NaOH solution. Since NaOH dissociates completely into two particles (Na⁺ and OH⁻), the osmolarity is given by: \( \text{Osmolarity} = \text{Molarity} \times \text{Number of particles per formula unit} \). Substitute \( \text{Molarity} = 0.30 \) M and \( \text{Number of particles} = 2 \).
Step 3: Convert the 3.0% (m/v) NaOH solution into molarity. The % (m/v) means 3.0 g of NaOH is dissolved in 100 mL of solution. First, calculate the number of moles of NaOH using its molar mass (NaOH has a molar mass of approximately 40.00 g/mol): \( \text{Moles of NaOH} = \frac{\text{Mass of NaOH}}{\text{Molar mass of NaOH}} \). Then, convert the volume from mL to L and calculate molarity: \( \text{Molarity} = \frac{\text{Moles of NaOH}}{\text{Volume in liters}} \).
Step 4: Calculate the osmolarity of the 3.0% (m/v) NaOH solution. Use the same formula as in Step 2: \( \text{Osmolarity} = \text{Molarity} \times \text{Number of particles per formula unit} \). Substitute the molarity calculated in Step 3 and \( \text{Number of particles} = 2 \).
Step 5: Compare the osmolarities of the two solutions. The solution with the higher osmolarity will have the greater total concentration of solute particles. Use the results from Steps 2 and 4 to determine which solution has the higher osmolarity.

비슷한 문제에 대한 검증된 영상 답변:
이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
영상 길이:
8m도움이 되었나요?
주요 개념
질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.
Osmolarity
Osmolarity is a measure of the total concentration of solute particles in a solution. It is expressed in osmoles per liter (osmol/L) and takes into account all particles that contribute to the solution's osmotic pressure, including ions and molecules. For ionic compounds like NaOH, which dissociates into sodium (Na+) and hydroxide (OH-) ions, the osmolarity is calculated by multiplying the molarity by the number of particles produced upon dissociation.
추천 영상:
가이드 코스
Osmolarity
Molarity
Molarity is a way to express the concentration of a solution, defined as the number of moles of solute per liter of solution (mol/L). In the case of NaOH, a 0.30 M solution means there are 0.30 moles of NaOH in one liter of solution. Understanding molarity is essential for calculating osmolarity, especially for ionic compounds that dissociate in solution.
추천 영상:
가이드 코스
Molarity
Mass/Volume Percent Concentration
Mass/volume percent concentration (m/v) is a way to express the concentration of a solution as the mass of solute per 100 mL of solution. For example, a 3.0% (m/v) NaOH solution means there are 3 grams of NaOH in 100 mL of solution. This concept is important for converting to molarity and subsequently calculating osmolarity, especially when comparing different types of concentration measurements.
추천 영상:
가이드 코스
Percent Concentrations Concept 1
관련 실천
교과서 질문
1391
views
교과서 질문
Calculate the mass needed for each of the following ion equivalents:
a. 0.25 Eq Ca2+
1159
views
교과서 질문
The concentration of Cl- ion in blood is approximately 100 mEq/L. How many milliliters of blood would be needed to obtain 1.0 g of Cl- ions?
1603
views
교과서 질문
What does it mean when we say that a 0.15 M NaCl solution is isotonic with blood, whereas distilled water is hypotonic?
2882
views
교과서 질문
Which of the following solutions will give rise to a greater osmotic pressure at equilibrium: 5.00 g of NaCl in 350.0 mL water or 35.0 g of glucose in 400.0 mL water? For NaCl, MW = 58.5 amu; for glucose, MW = 180 amu.
1313
views
교과서 질문
An isotonic solution must be approximately 0.30 osmol/L. How much KCl is needed to prepare 175 mL of an isotonic solution?
2380
views
