A city has a youth association with three programs for different age groups: Child (0-6), Tween (7-12), and Teen (13-18). They want to apportion the 30 new volunteers fairly based on the number of youths served by each of these programs. Use Jefferson’s Method to get a fair apportionment.

Child - 13; Tween - 10; Teen - 7

A city has a youth association with three programs for different age groups: Child (0-6), Tween (7-12), and Teen (13-18). They want to apportion the 30 new volunteers fairly based on the number of youths served by each of these programs. Use Jefferson’s Method to get a fair apportionment.

Welcome to the practice. For this problem, a city has a youth association with 3 programs for different age groups, child, tween, and teen. They want to apportion the 30 new volunteers fairly based on the number of youths served by each of these programs. We'd like to use Jefferson's method to get a fair apportionment. For step one, we're going to find our standard divisor. As a reminder, the standard divisor is equal to the total population. Divided by the number of items. To a portion To get the total population, we can add together the number of youths in each of these programs. So we get 1,543, plus 1,234, plus 897. And when we add these together, we get 3,674. Also, we can see that the number of items to apportion is 30, because there are 30 new volunteers that they're going to distribute between these programs. So our standard divisor is 3,674 divided by 30. And this gets us approximately 122.47. With step one all set, we move on to step two, where we want to choose our modified divisor. Again, we have to choose something that is lower than the standard divisor. Again, the standard divisor was 122.47, so we want to choose a modified divisor that is less than that. Because this is a three-digit standard divisor, we can go a little bit lower than just by 1 or 2. So maybe we end up trying something like 115, which is close to 122.47, but a bit lower. Now that we have our modified divisor, we move on to step three, where we find the modified quota for each group. We use this formula here where we take the group population and divide it by the modified divisor. So, for child, we end up getting 1,543 divided by 115, which gets us approximately 13.42. For tween, we take 1,234 and divide it by 115, getting us approximately 10.73. And finally, for teen, we take 897 and divide it by 115, getting approximately 7.8. Now that we found our modified quotas, step 3 is all set, and we move on to step 4, where we want to take those quotas and round down to get the modified lower quota. So for child, we round 13.42 down to 13, by removing that decimal part. Similarly, for tween, we're going to round 10.73 down to 10 by removing the decimal part, and 14, we're going to round 7.8 down to 7 by removing that decimal part. Now that we have all of our modified lower quotas, we move on to step 5, where we have to check to see if all items are apportioned and make sure that we haven't apportioned too few or too many. When we add together 13 + 10 + 7, we do end up getting 30, which was the number of volunteers we had to apportion. So, all of our items are apportioned and step 5 is all set. And we can say that the apportionment is 13 volunteers to the child program, 10 to the tween program, and 7 to the teen program. Great work.

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A city has a youth association with three programs for different age groups: Child (0-6), Tween (7-12), and Teen (13-18). They want to apportion the 30 new volunteers fairly based on the number of youths served by each of these programs. Use Jefferson’s Method to get a fair apportionment.

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