Skip to main content
Ch. 8 - Hypothesis Testing with Two Samples
Larson - Elementary Statistics: Picturing the World 8th Edition
Larson8th EditionElementary Statistics: Picturing the WorldISBN: 9780137493470Not the one you use?Change textbook
Chapter 8, Problem 8.1.11

In Exercises 11–14, test the claim about the difference between two population means and at the level of significance . Assume the samples are random and independent, and the populations are normally distributed.
Claim: μ1=μ2; α=0.1
Population statistics:σ1=3.4 and σ2=1.5
Sample Statistics: x̅1=16, n1=29, x̅2=14, n2=28

Verified step by step guidance
1
Identify the null hypothesis \(H_0\) and the alternative hypothesis \(H_a\). Since the claim is \(\mu_1 = \mu_2\), the hypotheses are: \(H_0: \mu_1 = \mu_2\) and \(H_a: \mu_1 \neq \mu_2\) (two-tailed test).
Determine the significance level \(\alpha = 0.1\) and find the corresponding critical z-values for a two-tailed test. These critical values define the rejection regions for the test statistic.
Calculate the standard error of the difference between the two sample means using the formula: \(SE = \sqrt{\frac{\sigma_1^2}{n_1} + \frac{\sigma_2^2}{n_2}}\) where \(\sigma_1 = 3.4\), \(n_1 = 29\), \(\sigma_2 = 1.5\), and \(n_2 = 28\).
Compute the test statistic (z-score) using the formula: \(z = \frac{\bar{x}_1 - \bar{x}_2 - (\mu_1 - \mu_2)}{SE}\) Since under \(H_0\), \(\mu_1 - \mu_2 = 0\), this simplifies to: \(z = \frac{16 - 14}{SE}\).
Compare the calculated z-value with the critical z-values. If the test statistic falls into the rejection region, reject \(H_0\); otherwise, do not reject \(H_0\). This will determine whether there is sufficient evidence to reject the claim that \(\mu_1 = \mu_2\) at the \(\alpha = 0.1\) significance level.

Verified video answer for a similar problem:

This video solution was recommended by our tutors as helpful for the problem above.
Video duration:
6m
Was this helpful?

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Hypothesis Testing for Two Population Means

This involves testing a claim about the difference between two population means using sample data. The null hypothesis typically states that the means are equal (μ1 = μ2), while the alternative suggests a difference. The test evaluates whether observed sample differences are statistically significant at a chosen significance level (α).
Recommended video:
Guided course
08:24
Difference in Means: Hypothesis Tests

Level of Significance (α)

The level of significance, α, is the threshold probability for rejecting the null hypothesis when it is true (Type I error). In this problem, α = 0.1 means there is a 10% risk of incorrectly rejecting the claim that the population means are equal. It determines the critical value for the test statistic.
Recommended video:
03:33
Finding Binomial Probabilities Using TI-84 Example 1

Known Population Standard Deviations and Z-Test

When population standard deviations (σ1 and σ2) are known, the Z-test is used to compare two means. The test statistic is calculated using sample means, population standard deviations, and sample sizes. This approach assumes normality and independence of samples to determine if the difference is significant.
Recommended video:
04:48
Population Standard Deviation Known
Related Practice
Textbook Question

Test the claim about the mean of the differences for a population of paired data at the level of significance α. Assume the samples are random and dependent, and the populations are normally distributed.

Claim: μd<0 , α=0.05 , Sample statistics: d̄ =1.5 , sd=3.2 , n=14

84
views
Textbook Question

Explain how to perform a two-sample t-test for the difference between two population means.

234
views
Textbook Question

Constructing Confidence Intervals for μ1-μ2. When the sampling distribution for x̅1-x̅2 is approximated by a t-distribution and the populations have equal variances, you can construct a confidence interval for μ1-μ2, as shown below.

Construct the indicated confidence interval for μ1-μ2 . Assume the populations are approximately normal with equal variances.

10K Race 

To compare the mean ages of male and female participants in a 10K race, you randomly select several ages from both sexes. The results are shown below. Construct a 95% confidence interval for the difference in mean ages of male and female participants in the race. (Adapted from Great Race)

47
views
Textbook Question

In Exercises 11–14, test the claim about the difference between two population means and at the level of significance . Assume the samples are random and independent, and the populations are normally distributed.

Claim: μ1<μ2; α=0.05

Population statistics:σ1=75 and σ2=105

Sample Statistics: x̅1=2435, n1=35, x̅2=2432, n2=90

80
views
Textbook Question

Parks and Mental Health In Exercises 13–18, use the figure, which shows the percentages from a survey of two hundred 18- to 24-year-olds in the United States who say that various park and recreation activities have a positive impact on their mental health. (Adapted from National Recreation and Park Association)



Socializing and Taking Classes At α=0.05, can you support the claim that the proportion of 18- to 24-year-olds who benefit mentally from socializing in parks is different from the proportion who benefit mentally from taking classes in parks?

48
views
Textbook Question

[APPLET] Tensile Strength

The tensile strength of a metal is a measure of its ability to resist tearing when it is pulled lengthwise. An experimental method of treatment produced steel bars with the tensile strengths (in newtons per square millimeter) listed below.

Experimental Method:

391 383 333 378 368 401 339 376 366 348

The conventional method produced steel bars with the tensile strengths (in newtons per square millimeter) listed below.

Conventional Method:

362 382 368 398 381 391 400410 396 411 385 385 395 371

At , α=0.01 can you support the claim that the experimental method of treatment makes a difference in the tensile strength of steel bars? Assume the population variances are equal.

48
views