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Ch. 5 - Trigonometric Identities
Lial - Trigonometry 12th Edition
Lial12th EditionTrigonometryISBN: 9780136552161Not the one you use?Change textbook
Chapter 6, Problem 5.1.18

Find sinθ.
tan θ = -(√7)/2, sec θ > 0

Verified step by step guidance
1
Identify the given information: \( \tan \theta = -\frac{\sqrt{7}}{2} \) and \( \sec \theta > 0 \). Recall that \( \sec \theta = \frac{1}{\cos \theta} \), so \( \sec \theta > 0 \) means \( \cos \theta > 0 \).
Determine the quadrant where \( \theta \) lies. Since \( \tan \theta \) is negative and \( \cos \theta \) is positive, \( \theta \) must be in the fourth quadrant (where cosine is positive and tangent is negative).
Use the identity relating tangent and sine and cosine: \( \tan \theta = \frac{\sin \theta}{\cos \theta} \). Let \( \cos \theta = x \), then \( \sin \theta = \tan \theta \times x = -\frac{\sqrt{7}}{2} x \).
Apply the Pythagorean identity: \( \sin^2 \theta + \cos^2 \theta = 1 \). Substitute \( \sin \theta = -\frac{\sqrt{7}}{2} x \) and \( \cos \theta = x \) to get \( \left(-\frac{\sqrt{7}}{2} x\right)^2 + x^2 = 1 \).
Solve the equation for \( x \) (which is \( \cos \theta \)), then use \( \sin \theta = -\frac{\sqrt{7}}{2} x \) to find \( \sin \theta \). Remember to choose the sign of \( \sin \theta \) consistent with the quadrant (fourth quadrant means \( \sin \theta < 0 \)).

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Trigonometric Ratios and Their Relationships

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