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Ch. 3 - Derivatives
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Not the one you use?Change textbook
Chapter 3, Problem 3.9.4

Finding Linearizations


In Exercises 1–5, find the linearization L(x) of f(x) at x = a.


f(x) = ∛x, a = −8

Verified step by step guidance
1
Identify the function f(x) = ∛x and the point of interest x = a = -8.
Recall the formula for the linearization of a function at a point: L(x) = f(a) + f'(a)(x - a).
Calculate f(a) by substituting a = -8 into the function: f(-8) = ∛(-8).
Find the derivative f'(x) of the function f(x) = ∛x. Use the power rule for derivatives: f(x) = x^(1/3) implies f'(x) = (1/3)x^(-2/3).
Evaluate the derivative at the point a = -8: f'(-8) = (1/3)(-8)^(-2/3). Substitute f(a) and f'(a) into the linearization formula to find L(x).

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Linearization

Linearization is the process of approximating a function near a given point using the tangent line at that point. The linearization of a function f(x) at x = a is given by L(x) = f(a) + f'(a)(x - a). This provides a simple linear model that approximates the function's behavior close to x = a.
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Derivative

The derivative of a function, denoted as f'(x), represents the rate at which the function's value changes with respect to changes in x. It is the slope of the tangent line to the function at any given point. For linearization, the derivative at x = a, f'(a), is crucial as it determines the slope of the linear approximation.
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Cube Root Function

The cube root function, f(x) = ∛x, is a type of root function where the output is the number that, when cubed, gives x. Understanding its behavior, especially around specific points like x = -8, is essential for calculating derivatives and linearizations. The function is continuous and differentiable for all real numbers, which facilitates finding its linear approximation.
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Graphs of Common Functions