Textbook Question
Limits of sums Use the definition of the definite integral to evaluate the following definite integrals. Use right Riemann sums and Theorem 5.1.
ā«āā“ (šĀ²ā1) dš
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Ch. 5 - Integration
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243
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Table of contents
- Ch. 1 - Functions210
- Ch. 2 - Limits371
- Ch. 3 - Derivatives633
- Ch. 4 - Applications of the Derivative412
- Ch. 5 - Integration328
- Ch. 6 - Applications of Integration331
- Ch. 7 - Logarithmic, Exponential Functions, and Hyperbolic Functions177
- Ch. 8 - Integration Techniques394
- Ch. 9 - Differential Equations179
- Ch. 10 - Sequences and Infinite Series339
- Ch. 11 - Power Series218
- Ch.12 - Parametric and Polar Curves215
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Not the one you use?Change textbook
Chapter 5, Problem 5.3.106
{Use of Tech} Areas of regions Find the area of the region š
bounded by the graph of Ę and the š-axis on the given interval. Graph Ę and show the region š
.
Ę(š) = šĀ² (š ā 2) on [ ā1 , 3]
Verified step by step guidance1
First, understand that the region \( R \) is bounded by the graph of the function \( f(x) = x^{2}(x - 2) \) and the x-axis over the interval \( [-1, 3] \). Our goal is to find the total area between the curve and the x-axis on this interval.
Next, find the points where the graph intersects the x-axis within the interval. These are the roots of \( f(x) = 0 \). Solve \( x^{2}(x - 2) = 0 \) to find these points.
Once the roots are identified, split the interval \( [-1, 3] \) into subintervals based on these roots. This is important because the function may be above or below the x-axis on different subintervals, and the area calculation requires considering the absolute value of the integral on each subinterval.
Set up the definite integrals for each subinterval, integrating \( |f(x)| \) with respect to \( x \). This means you will integrate \( f(x) \) where it is positive and \( -f(x) \) where it is negative to ensure the area is positive.
Finally, compute each integral separately and sum their absolute values to find the total area of the region \( R \). Remember, the area is the sum of the magnitudes of these integrals, not just their algebraic sum.
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3mKey Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Definite Integral and Area Under a Curve
The definite integral of a function over an interval represents the net area between the graph of the function and the x-axis. When the function is positive, the integral gives the area above the x-axis; when negative, it subtracts area below the x-axis. To find the total area of a region bounded by the curve and the x-axis, one often integrates the absolute value of the function or splits the integral at points where the function crosses the axis.
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05:43
Definition of the Definite Integral
Finding Zeros of the Function
Identifying where the function equals zero within the given interval is crucial because these points mark where the graph intersects the x-axis. These zeros divide the interval into subintervals where the function maintains a consistent sign (positive or negative). This helps in correctly calculating areas by integrating over each subinterval and taking absolute values if necessary.
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Graphing the Function to Visualize the Region
Sketching or graphing the function over the specified interval helps visualize the region bounded by the curve and the x-axis. It reveals where the function is above or below the axis, the shape of the region, and the points of intersection. This visual aid is essential for setting up the integral correctly and understanding the problem context.
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Related Practice
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