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Ch. 6 - Applications of Integration
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Not the one you use?Change textbook
Chapter 6, Problem 6.5.35b

Functions from arc length What differentiable functions have an arc length on the interval [a, b] given by the following integrals? Note that the answers are not unique. Give a family of functions that satisfy the conditions.
b. ∫a^b √1+36 cos² 2xdx

Verified step by step guidance
1
Recall the formula for the arc length of a differentiable function \( y = f(x) \) on the interval \([a,b]\): \[ L = \int_a^b \sqrt{1 + \left(\frac{dy}{dx}\right)^2} \, dx \]
Compare the given integral for arc length: \[ \int_a^b \sqrt{1 + 36 \cos^2(2x)} \, dx \] with the general formula. This means: \[ 1 + \left(\frac{dy}{dx}\right)^2 = 1 + 36 \cos^2(2x) \]
From the equality above, isolate \( \frac{dy}{dx} \): \[ \left(\frac{dy}{dx}\right)^2 = 36 \cos^2(2x) \] which implies \[ \frac{dy}{dx} = \pm 6 \cos(2x) \]
Integrate \( \frac{dy}{dx} = \pm 6 \cos(2x) \) with respect to \( x \) to find the family of functions: \[ y = \pm 6 \int \cos(2x) \, dx + C \]
Recall that \( \int \cos(2x) \, dx = \frac{1}{2} \sin(2x) + C \), so the family of functions is: \[ y = \pm 3 \sin(2x) + C \] where \( C \) is an arbitrary constant.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Arc Length Formula

The arc length of a differentiable function y = f(x) on [a, b] is given by the integral ∫_a^b √(1 + (f'(x))²) dx. This formula measures the length of the curve by summing infinitesimal line segments, where the integrand involves the derivative of the function.
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Relating the Integrand to the Derivative

To find functions with a given arc length integral, identify the expression inside the square root as 1 + (f'(x))². Equate this to the given integrand to solve for f'(x), which helps determine the family of functions whose derivatives satisfy the condition.
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Solving Differential Equations for Families of Functions

Once f'(x) is found, integrate it to obtain the general form of f(x). Since integration introduces an arbitrary constant, the solution represents a family of functions, not a unique one, matching the problem's requirement for multiple solutions.
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