Solve each rational inequality in Exercises 43–60 and graph the solution set on a real number line. Express each solution set in interval notation. (x+4)/x>0
Table of contents
- 0. Review of Algebra4h 18m
- 1. Equations & Inequalities3h 18m
- 2. Graphs of Equations1h 43m
- 3. Functions2h 17m
- 4. Polynomial Functions1h 44m
- 5. Rational Functions1h 23m
- 6. Exponential & Logarithmic Functions2h 28m
- 7. Systems of Equations & Matrices4h 5m
- 8. Conic Sections2h 23m
- 9. Sequences, Series, & Induction1h 22m
- 10. Combinatorics & Probability1h 45m
1. Equations & Inequalities
Linear Inequalities
Problem 68
Textbook Question
Solve each inequality in Exercises 65–70 and graph the solution set on a real number line. 1/(x + 1) > 2/(x - 1)
Verified step by step guidance1
Start by writing the inequality clearly: \(\frac{1}{x + 1} > \frac{2}{x - 1}\).
Bring all terms to one side to have zero on the other side: \(\frac{1}{x + 1} - \frac{2}{x - 1} > 0\).
Find a common denominator, which is \((x + 1)(x - 1)\), and combine the fractions: \(\frac{(x - 1) - 2(x + 1)}{(x + 1)(x - 1)} > 0\).
Simplify the numerator: \((x - 1) - 2(x + 1) = x - 1 - 2x - 2 = -x - 3\), so the inequality becomes \(\frac{-x - 3}{(x + 1)(x - 1)} > 0\).
Determine the critical points by setting numerator and denominator equal to zero: numerator \(-x - 3 = 0\) gives \(x = -3\), denominator \((x + 1)(x - 1) = 0\) gives \(x = -1\) and \(x = 1\). Use these points to test intervals on the number line to find where the inequality holds.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Solving Rational Inequalities
Rational inequalities involve expressions with variables in the denominator. To solve them, first bring all terms to one side to form a single rational expression, then determine where this expression is positive or negative by analyzing its critical points.
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Finding Critical Points and Domain Restrictions
Critical points occur where the numerator or denominator equals zero. These points divide the number line into intervals to test. Also, values that make the denominator zero are excluded from the domain, as they cause undefined expressions.
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Graphing Solution Sets on a Number Line
After determining intervals where the inequality holds, represent the solution set on a real number line. Use open or closed circles to indicate whether endpoints are included or excluded, and shade the regions that satisfy the inequality.
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