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Ch. 4 - Gene Interaction
Chapter 4, Problem 31

Human ABO blood type is determined by three alleles, two of which (I^A and I^B) produce gene products that modify the H antigen produced by protein activity of an independently assorting H gene. A rare abnormality known as the 'Bombay phenotype' is the result of epistatic interaction between the gene for the ABO blood group and the H gene. Individuals with the Bombay phenotype appear to have blood type O based on the inability of both anti-A antibody and anti-B antibody to detect an antigen. The apparent blood type O in Bombay phenotype is due to the absence of H antigen as a result of homozygous recessive mutations of the H gene. Individuals with the Bombay phenotype have the hh genotype. Use the information above to make predictions about the outcome of the cross shown below.
IᴬIᴮHh×IᴬIᴮHh

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1
Determine the genotypes of the parents. Both parents are IᴬIᴮHh, meaning they are heterozygous for the H gene (Hh) and heterozygous for the ABO blood group alleles (IᴬIᴮ).
Set up a Punnett square for the H gene. Since both parents are Hh, the possible genotypes for their offspring are HH, Hh, and hh. The hh genotype results in the Bombay phenotype, regardless of the ABO alleles.
Set up a separate Punnett square for the ABO alleles. Since both parents are IᴬIᴮ, the possible genotypes for their offspring are IᴬIᴬ, IᴬIᴮ, IᴮIᴮ, and ii. These genotypes correspond to blood types A, AB, B, and O, respectively, but only if the H antigen is present (H allele).
Combine the results of the two Punnett squares. For each combination of ABO genotype and H genotype, determine the phenotype. If the H genotype is hh, the individual will have the Bombay phenotype (appearing as blood type O) regardless of their ABO genotype.
Calculate the probabilities of each phenotype by multiplying the probabilities from the ABO Punnett square and the H gene Punnett square. For example, the probability of a Bombay phenotype (hh) is determined by the hh genotype (1/4) combined with any ABO genotype.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

ABO Blood Group System

The ABO blood group system is determined by the presence of specific antigens on the surface of red blood cells, which are encoded by three alleles: I^A, I^B, and i. The I^A and I^B alleles are co-dominant, meaning that both can be expressed simultaneously, resulting in blood types A (I^A I^A or I^A i), B (I^B I^B or I^B i), AB (I^A I^B), or O (ii). Understanding this system is crucial for predicting blood type inheritance in offspring.
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Epistasis

Epistasis refers to the interaction between genes where the expression of one gene is affected by one or more other genes. In the case of the Bombay phenotype, the H gene's product is necessary for the expression of A and B antigens. Individuals with the hh genotype lack the H antigen, leading to a phenotype that appears as blood type O, despite having I^A and I^B alleles. This concept is essential for understanding how gene interactions can influence phenotypic outcomes.
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Genotype and Phenotype

Genotype refers to the genetic constitution of an individual, while phenotype is the observable physical or biochemical characteristics resulting from the genotype and environmental influences. In the context of the Bombay phenotype, the genotype hh leads to the absence of the H antigen, resulting in a phenotype that is indistinguishable from blood type O. This distinction is vital for predicting the phenotypic ratios in genetic crosses.
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Related Practice
Textbook Question

Dr. Ara B. Dopsis and Dr. C. Ellie Gans are performing genetic crosses on daisy plants. They self-fertilize a blue-flowered daisy and grow 100 progeny plants that consist of 55 blue-flowered plants, 22 purple-flowered plants, and 23 white-flowered plants. Dr. Dopsis believes this is the result of segregation of two alleles at one locus and that the progeny ratio is 1:2:1. Dr. Gans thinks the progeny phenotypes are the result of two epistatic genes and that the ratio is 9:3:4.

The two scientists ask you to resolve their conflict by performing chi-square analysis on the data for both proposed genetic mechanisms. For each proposed mechanism, fill in the values requested on the form the researchers have provided for your analysis.

Use the form below to calculate chi-square for the 1:2:1 hypothesis of Dr. Sophila.

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Textbook Question

Dr. Ara B. Dopsis and Dr. C. Ellie Gans are performing genetic crosses on daisy plants. They self-fertilize a blue-flowered daisy and grow 100 progeny plants that consist of 55 blue-flowered plants, 22 purple-flowered plants, and 23 white-flowered plants. Dr. Dopsis believes this is the result of segregation of two alleles at one locus and that the progeny ratio is 1:2:1. Dr. Gans thinks the progeny phenotypes are the result of two epistatic genes and that the ratio is 9:3:4.

The two scientists ask you to resolve their conflict by performing chi-square analysis on the data for both proposed genetic mechanisms. For each proposed mechanism, fill in the values requested on the form the researchers have provided for your analysis.

Use the form below to calculate chi-square for the 9:3:4 hypothesis of Dr. Gans.

421
views
Textbook Question

Dr. Ara B. Dopsis and Dr. C. Ellie Gans are performing genetic crosses on daisy plants. They self-fertilize a blue-flowered daisy and grow 100 progeny plants that consist of 55 blue-flowered plants, 22 purple-flowered plants, and 23 white-flowered plants. Dr. Dopsis believes this is the result of segregation of two alleles at one locus and that the progeny ratio is 1:2:1. Dr. Gans thinks the progeny phenotypes are the result of two epistatic genes and that the ratio is 9:3:4.

The two scientists ask you to resolve their conflict by performing chi-square analysis on the data for both proposed genetic mechanisms. For each proposed mechanism, fill in the values requested on the form the researchers have provided for your analysis.


What is your conclusion regarding these two genetic hypotheses: the 1:2:1 hypothesis and the 9:3:4 hypothesis?

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Textbook Question

In rabbits, albinism is an autosomal recessive condition caused by the absence of the pigment melanin from skin and fur. Pigmentation is a dominant wild-type trait. Three pure-breeding strains of albino rabbits, identified as strains 1, 2, and 3, are crossed to one another. In the table below, F₁ and F₂ progeny are shown for each cross. Based on the available data, propose a genetic explanation for the results. As part of your answer, create genotypes for each albino strain using clearly defined symbols of your own choosing. Use your symbols to diagram each cross, giving the F₁ and F₂ genotypes. <>

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Textbook Question

Dr. O. Sophila, a close friend of Dr. Ara B. Dopsis, reviews the results Dr. Dopsis obtained in his experiment with iris plants described in Genetic Analysis 4.3. Dr. Sophila thinks the F₂ progeny demonstrate that a single gene with incomplete dominance has produced a 1:2:1 ratio. Dr. Dopsis insists his proposal of recessive epistasis producing a 9:4:3 ratio in the F₂ is correct. To test his proposal, Dr. Dopsis examines the F₂ data under the assumptions of the single-gene incomplete dominance model using chi-square analysis. Calculate and interpret this chi-square value. Can Dr. Dopsis reject the single-gene incomplete dominance model on the basis of this analysis? Explain why or why not.

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Textbook Question

In a breed of domestic cattle, horns can appear on males and on females. Males and females can also be hornless. The following crosses are performed with parents from pure-breeding lines.

Explain the inheritance of this phenotype in cattle, and assign genotypes to all cattle in each cross.

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