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Ch. 6 - Genetic Analysis and Mapping in Bacteria and Bacteriophages
Sanders - Genetic Analysis: An Integrated Approach 3rd Edition
Sanders3rd EditionGenetic Analysis: An Integrated ApproachISBN: 9780135564172Not the one you use?Change textbook
Chapter 6, Problem 22f

An attribute of growth behavior of eight bacteriophage mutants (1 to 8) is investigated in experiments that establish coinfection by pairs of mutants. The experiments determine whether the mutants complement one another (+) or fail to complement (-). These eight mutants are known to result from point mutation. The results of the complementation tests are shown below.
Table showing complementation results of eight bacteriophage mutants in genetics experiments.
Gene-mapping information identifies mutations 2 and 3 as the flanking markers in this group of genes. Assuming these mutations are on opposite ends of the gene map, determine the order of mutations in the region of the chromosome.

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Step 1: Understand the complementation test. Complementation occurs when two mutations in different genes restore the wild-type phenotype when combined. If two mutations fail to complement, they are likely in the same gene.
Step 2: Analyze the first table. The table shows the complementation results for eight bacteriophage mutants. A '-' indicates failure to complement (same gene), and a '+' indicates complementation (different genes). Use this information to group mutations into distinct genes.
Step 3: Use the gene-mapping information. Mutations 2 and 3 are flanking markers, meaning they are located at opposite ends of the gene map. This implies that the order of mutations must be determined relative to these markers.
Step 4: Analyze the second table. The second table provides additional complementation results for mutants labeled A to D. Use this data to refine the grouping and order of mutations within the gene map.
Step 5: Combine the data from both tables. Using the complementation results and the flanking marker information, deduce the order of mutations along the chromosome. Ensure that mutations 2 and 3 are positioned at opposite ends of the map.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Complementation Testing

Complementation testing is a genetic technique used to determine whether two mutations that produce a similar phenotype are in the same gene or in different genes. If two mutants complement each other, it indicates that they are in different genes, as the presence of one functional copy can restore the normal function. Conversely, if they fail to complement, it suggests that both mutations affect the same gene.
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Point Mutations

Point mutations are changes in a single nucleotide base pair in the DNA sequence. These mutations can result from various factors, including errors during DNA replication or exposure to mutagens. Point mutations can lead to different phenotypes, depending on their location and effect on gene function, and are often the basis for studying genetic variation and complementation in organisms.
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Gene Mapping

Gene mapping is the process of determining the location of genes on a chromosome and the distances between them. It often involves analyzing the results of complementation tests and recombination frequencies to establish the order of mutations. In this context, identifying mutations 2 and 3 as flanking markers helps in deducing the arrangement of other mutations within the gene region, providing insights into genetic linkage and function.
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Related Practice
Textbook Question

An attribute of growth behavior of eight bacteriophage mutants (1 to 8) is investigated in experiments that establish coinfection by pairs of mutants. The experiments determine whether the mutants complement one another (+) or fail to complement (-). These eight mutants are known to result from point mutation. The results of the complementation tests are shown below.

In each coinfection identified as a failure to complement (−) in the table, researchers see evidence of recombination producing wild-type growth. How do the researchers distinguish between wild-type growth resulting from complementation and wild-type growth that is due to recombination?

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Textbook Question

An attribute of growth behavior of eight bacteriophage mutants (1 to 8) is investigated in experiments that establish coinfection by pairs of mutants. The experiments determine whether the mutants complement one another (+) or fail to complement (-). These eight mutants are known to result from point mutation. The results of the complementation tests are shown below.

A new mutation, designated 9, fails to complement mutants 1, 3, 5, 7, and 8. Wild-type recombinants form between mutant 9 and mutations 3, 5, and 8; however, no wild-type recombinants form between mutant 9 and mutations 1 and 7. What kind of mutation is mutant 9? Explain your reasoning.

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Textbook Question

An attribute of growth behavior of eight bacteriophage mutants (1 to 8) is investigated in experiments that establish coinfection by pairs of mutants. The experiments determine whether the mutants complement one another (+) or fail to complement (-). These eight mutants are known to result from point mutation. The results of the complementation tests are shown below.

New mutation 10 fails to complement mutants 1, 4, 5, 6, 8, and 9. Mutant 10 forms wild-type recombinants with mutants 1, 5, and 6, but not with mutants 4 and 8. Mutant 9 and mutant 10 form wild-type recombinants. What kind of mutation is mutant 10? Explain your reasoning.

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Textbook Question

Synthesis of the amino acid histidine is a multistep anabolic pathway that uses the products of 13 genes (hisA to hisM) in E. coli. Two independently isolated his- E. coli mutants, designated his1⁻ and his2⁻ are studied in a conjugation experiment. A his⁺ F' donor strain that carries a copy of the hisJ gene on the plasmid is mated with a his1⁻ recipient strain in Experiment 1 and with a his2⁻ recipient in Experiment 2. The exconjugants are grown on plates lacking histidine. Growth is observed among the exconjugants of Experiment 2 but not among those of Experiment 1.

Why is growth observed in Experiment 2 but not in Experiment 1?

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Textbook Question

Synthesis of the amino acid histidine is a multistep anabolic pathway that uses the products of 13 genes (hisA to hisM) in E. coli. Two independently isolated his- E. coli mutants, designated his1⁻ and his2⁻ are studied in a conjugation experiment. A his⁺ F' donor strain that carries a copy of the hisJ gene on the plasmid is mated with a his1⁻ recipient strain in Experiment 1 and with a his2⁻ recipient in Experiment 2. The exconjugants are grown on plates lacking histidine. Growth is observed among the exconjugants of Experiment 2 but not among those of Experiment 1.

What is the genotype of exconjugants in Experiment 2?

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Textbook Question

The phage P1 is used as a generalized transducing phage in an experiment combining a donor strain of E. coli of genotype leu⁺ phe⁺ ala⁺ and a recipient strain that is leu⁻ phe⁻ ala⁻. In separate experiments, transductants are selected for leu⁺ (Experiment A), for ala⁺ (Experiment B), and for phe⁺ (Experiment C). Following selection, transductant genotypes for the unselected markers are identified. The selection experiment results below show the frequency of each genotype.

What compound or compounds are added to the minimal medium to select for transductants in Experiments A, B, and C?

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