Name the following compounds:
e.

Question

Name the following compounds:

e.

f. Structural formula of an organic compound with multiple hydroxyl (OH) groups and carbon chains.

Accepted Answer

Welcome back everyone. Our next question says, what are the names of the compound shown below? And we have a compound one and a compound two with choices A through D with different possible names for both of them. So I won't read them all out loud. We'll work through them as we look at these compounds and figure out what their names should be. So compound one, we see we have a triple bond and sort of a long straight line and several branches at the end. So our first job will be to find out what is our longest continuous chain. So I'll use the highlighter function to look for that. I'll start on this big long linear stretch through my triple bond up to the point at which I've got several branches going off. And I have for my branches, I have two methyl and one ethyl. So I'm going to go into the ethyl branch as that will give me the longest possible chain. So I've traced my longest possible chain. Let's look how many carbons it has. And I'm going to go ahead and erase the continuous line I made and go ahead and use sort of highlighted dots to indicate each of my carbons to help me keep track of them, especially with triple bonds where they're drawn all in a line like this. You want to remember how many carbons total you have as the triple bonds don't present with a corner the way we usually see in skeletal structures. So we have one starting from the right side, then two is the first carbon involved in the triple bond three at the other end of the triple bond four, which is the point at which the substituents branch off. And then we're going off into the ethyl chain to make that carbon five and carbon six. So we have six carbons total with carbon one being at the end closest to the triple bond, carbon six at the other end, that puts our triple bond at carbon two between two and three. So with six carbons and our double bond, I'll put DB at C four, we know that our base name here would be, it's a hex sign. So we have hex or not. That's carbon for, excuse me, our triple, our and it's not a double bond either. It's a triple bond TB add carbon two again, tricky to keep track sometimes of which order you're going in. So we have a hex sign and it's at, so it's hex and hyphen two and then Yne, that's our base name. And now we just need to name our substituents. So we have two methyl groups there and that is at carbon 41234. So it would be 44 hyphen dye methyl. And that all runs together with no space 44 dimethyl hex two line. So when we work our way through our answer choices, we see in choice. A number one is labeled 44 by methyl hex two, I. So that's correct. In choice B it says 44 dimethyl hex three I. So it has the triple bond in the wrong location. So we can cross out choice B. Choice C, we have 33 dimethyl hex two line. So the methyl groups are in the wrong location. So eliminate choice C. And in choice D, we have 33 dimethyl hex four. So both the methyl groups and the triple bond are in the wrong location. So D can be crossed out as well. Well, even without looking at our second compound, we're already down to only one answer. Choice. A so good example, why it's always good on a test and multiple choice to look at those multiple choice answers and see if you can eliminate answers and get down to something without working through the entire problem, but we are not on a test. So we're going to be thorough and look at our other molecule. So again, first step, find the longest continuous chain, we have another triple bond this time at the carbon one. So it's easy to know, to start at the end of that triple bond, tracing a straight line through the triple bond onto the carbon that has a methyl group and a bromine. So we can just count that methyl group in our chain. So let's erase my continuous line and look at how many carbons we have. We have carbon one participating in the triple bond carbon two at the other end, carbon three, which has a bromine. And then we go on to carbon four with that sort of metal group there. So four carbons total or carbon and the triple bond TB at carbon one. So we have four carbons is butane, in this case, butane. So we have Bute hyphen one Iyne, we just need to label our substituents of which there's only one that's a bromine and carbon three. So we'd have three bromo but one I and indeed in choice A that is the answer for compound two. So we have our final answer here as we expected. Choice. A 44 dimethyl hex two I four, number one. And for number 23, bromo, butte 19. See you in the next video.

Name the following compounds:
e.
f.

Key Concepts

Nomenclature

Functional Groups

Structural Representation

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