There are two things wrong with the following structure. What are they?

Question

Chemical structure of a hydrocarbon with two identified errors in its representation.

Accepted Answer

All right. Hi, everyone. So this question is asking us what is wrong in this given structure? Option A says Bromine carbon bonding option B says exceeding carbon valency. Option C says both A and B and option D says none of the above. So when we consider the structure that's given to us, right, there are two noteworthy regions in this compound. If I consider my ring structure, there is one area where a carbon in the ring is connecting to a bromine and another portion of the molecule that contains a car bal or ac double bond oxygen and an oh group attached. So to understand why these regions of the molecule stand out, why they look strange. We have to recall the tendencies of these atoms when it comes to bonding or their preferences, right? Bromine, for example, if you recall is a halogen, which means that it has seven valence electrons before it begins bonding with other atoms. Now, because bromine only requires one valence electron to complete its octet bromine and other halogens for that matter generally form only one COVID pond because if it already has seven valent electrons, then one covalent bond provides it with the one electron that it is missing to achieve a full octet. But in this case, I can see that there is a double bond between carbon and Bromy. Now this goes against the preference of bromine to have only one covalent bond to achieve the full octet. So that's going to be incorrect, right? Because that violates or goes against how bromine would actually bond with carbon in this case. And also we have to consider the bonding preferences of carbon because recall that carbon is tetravalent, right? It can have a maximum of four bonds to other atoms. Now, when counting the number of bonds, a certain carbon atom has recall the double bonds count as two and triple bonds count as three. So if I consider the carbon on the right side of my ring structure, here, I have one double ban thought thats two as well as three single bonds, two to the other carbons in the ring and one more to the oxygen of the o group. So that's one double bond. So that's two and three single bonds. So that gives me a total of five bonds on one carbon. And that would be incorrect because having five bonds exceeds the four, sorry, the four bond maximum that carbon can have right can maintain. So the structure given to us on the screen here is correct. For those two reasons, the bromine carbon bonding is wrong because bromine would have one single bond to carbon and the carbon valency is exceeded because one carbon in the ring has five bonds, which goes against the four bond maximum. So our answer, it's going to be option C in the multiple choice because both A and B are true about the inaccuracies of the structure. And with that being said, thank you so very much for watching and I hope you found this helpful.

There are two things wrong with the following structure. What are they?

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