There are two isomeric triacylglycerol molecules whose components are glycerol, one palmitic acid unit, and two stearic acid units. Draw the structures of both, and explain how they differ.

Question

Accepted Answer

Welcome back everyone to another video, a Tr Ayl Glycerol molecule consists of Glycerol, one mistic acid unit and two pome acid units. There are two possible isomers for this molecule draw these structures and explain how they differ. So basically, we are given a Tr Azy glycerol. So we want to begin our problem by drawing Glycerol, we have to understand that it has three carbons, right. So we are drawing three carbons, ch two followed by ch followed by another ch two. And because this is tria glycerol, we want to replace the hygen atoms from each alcohol group with carbona. So we're simply adding three Carbonis bondage, those oxygens. So carbon double bonded oxygen in each case. And now our goal is to simply determine the identity of the alky group bonne to carbonel carbon. And because we have two possible structures, we're going to do the same or another fragment that we have drawn. And now it states that we have one mistic acid unit. We simply want to recall that mistic acid has a total of 14 carbons. So we count carbon carbon as number one. Then we will have a linear, basically straight chain that is fully saturated. So a specific number of C two units followed by ch three, right, the terminal metal. So if we expect to have 14 carbons, we subtract one, this gives us 13, we subtract one more from the muscle group, this gives us 12, subtract one seed two that gives us 11. And this means that there are 11 more seeds to units. And now there are two palmitic acid units. And once again, it is a saturated carboxylic acid that has a linear chain. So we want to add s to followed by some number of CH two again. And then ch three and now palmitic acid. Well, essentially it has 16 carbons. So once again, we subtract 3123 and this gives us 13 seeds to units because we have two of them. We're adding exactly the same chain for carbon number three of Glycerol, ch two, ch 2, 13 times CH three. And now this is structure one or structure t we want to draw a constitutional isomer. Well, basically, we want to derive an isomer that contains mistic acid unit bonded to carbon number two of Glycerol, right? We're changing the linkage bonding it to carbon. Number three will give us the same molecule because we can simply flip it right. And therefore we can state that the first carbon is going to have pome acid. So ch two CH two, 13 times CH three followed by mistic acid. Ch two ch 211 ch three. And then once again, palmitic acid C two C two 13 C three. This is structured team and now let's identify the differences. So for structure one, we can notice that mic acid is bonded to carbon number one of glycerol or structure two is bonded at carbon number two. And we can also understand that the first structure has a chiral carbon that contains four different substitutions. So this molecule is chiral, it does not have any internal plane of symmetry. The second molecule does not have any chiral carbon that because carbon number two has two, exactly same units that we can see right. So essentially it is an a chiral symmetrical molecule and also be the differences. Thank you for watching.

There are two isomeric triacylglycerol molecules whose components are glycerol, one palmitic acid unit, and two stearic acid units. Draw the structures of both, and explain how they differ.

Verified video answer for a similar problem:

Key Concepts

Triacylglycerol Structure

Isomerism

Fatty Acid Composition