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Ch. 5 - Integration
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Not the one you use?Change textbook
Chapter 5, Problem 5.3.20a

Area functions for linear functions Consider the following functions Ζ’ and real numbers a (see figure).
(a) Find and graph the area function A (𝓍) = βˆ«β‚Λ£ Ζ’(t) dt .

Ζ’(t) = 2t + 5 , a = 0

Verified step by step guidance
1
Step 1: Understand the problem. The goal is to find the area function A(x) = βˆ«β‚Λ£ Ζ’(t) dt, where Ζ’(t) = 2t + 5 and a = 0. This represents the area under the curve of Ζ’(t) from t = a to t = x.
Step 2: Set up the integral. Substitute the given function Ζ’(t) = 2t + 5 into the integral: A(x) = βˆ«β‚€Λ£ (2t + 5) dt.
Step 3: Break the integral into parts. Use the linearity of integration to separate the terms: A(x) = βˆ«β‚€Λ£ 2t dt + βˆ«β‚€Λ£ 5 dt.
Step 4: Compute each integral. For βˆ«β‚€Λ£ 2t dt, use the power rule for integration: ∫ t^n dt = (t^(n+1))/(n+1). For βˆ«β‚€Λ£ 5 dt, treat 5 as a constant and integrate: ∫ c dt = c * t.
Step 5: Combine the results and simplify. After evaluating the definite integrals, combine the terms to express A(x) as a function of x. This will give the area function A(x).

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Definite Integral

A definite integral represents the signed area under a curve between two points on the x-axis. It is denoted as βˆ«β‚Λ£ f(t) dt, where 'a' is the lower limit and 'x' is the upper limit. This concept is fundamental in calculating the area function A(x), which accumulates the area under the function f(t) from 'a' to 'x'.
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Definition of the Definite Integral

Area Function

The area function A(x) is defined as the integral of a function f(t) from a fixed point 'a' to a variable point 'x'. It quantifies the total area under the curve of f(t) from 'a' to 'x'. In this case, with f(t) = 2t + 5, A(x) will yield a linear function representing the area as 'x' changes.
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Finding Area When Bounds Are Not Given

Graphing Area Functions

Graphing the area function A(x) involves plotting the accumulated area under the curve of f(t) as 'x' varies. The resulting graph typically shows how the area increases with 'x', reflecting the behavior of the original function. For linear functions like f(t) = 2t + 5, the area function will also be linear, making it easier to visualize the relationship between the two.
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Related Practice
Textbook Question

Using properties of integrals Use the value of the first integral I to evaluate the two given integrals. 

I = βˆ«β‚€ΒΉ (𝓍³ ― 2𝓍) d𝓍 = ―3/4

(a) βˆ«β‚€ΒΉ (4𝓍―2𝓍³) d𝓍

110
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Textbook Question

Area functions for linear functions Consider the following functions Ζ’ and real numbers a (see figure).                                                                                           

                                                                                                                                                                                     

 (a) Find and graph the area function A (𝓍) = βˆ«β‚Λ£ Ζ’(t) dt .                                                                                                                               

                                                                                                                                                                               

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 Ζ’(t) = 4t + 2 , a = 0

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Textbook Question

Properties of integrals Use only the fact that βˆ«β‚€β΄ 3𝓍 (4 ―𝓍) d𝓍 = 32, and the definitions and properties of integrals, to evaluate the following integrals, if possible.

(a) βˆ«β‚„β° 3𝓍(4 ― 𝓍) d(𝓍)

61
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Textbook Question

Working with area functions Consider the function Ζ’ and its graph.

(a) Estimate the zeros of the area function A(𝓍) = βˆ«β‚€Λ£ Ζ’(t) dt , for 0 ≀ 𝓍 ≀ 10 .


36
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Textbook Question

Sigma notation Express the following sums using sigma notation. (Answers are not unique.)

(a) 1 + 2 + 3 + 4 + 5

110
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Textbook Question

Using properties of integrals Use the value of the first integral I to evaluate the two given integrals. 

I = βˆ«β‚€^Ο€/2 (cos ΞΈ ― 2 sin ΞΈ) dΞΈ = ―1

(a) βˆ«β‚€^Ο€/2 (2 sin ΞΈ ― cos ΞΈ) dΞΈ

82
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