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Ch. 8 - Integration Techniques
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Not the one you use?Change textbook
Chapter 8, Problem 8.5.57

23-64. Integration Evaluate the following integrals.
57. ∫ (x³ + 5x)/(x² + 3)² dx

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Start by examining the integral \( \int \frac{x^{3} + 5x}{(x^{2} + 3)^{2}} \, dx \). Notice that the denominator is \( (x^{2} + 3)^{2} \), which suggests a substitution involving \( x^{2} + 3 \) might simplify the integral.
Let \( u = x^{2} + 3 \). Then, compute the differential \( du = 2x \, dx \), which implies \( x \, dx = \frac{du}{2} \). This substitution will help rewrite parts of the integral in terms of \( u \) and \( du \).
Rewrite the numerator \( x^{3} + 5x \) as \( x(x^{2} + 5) \). Using the substitution, express \( x^{3} + 5x = x(x^{2} + 5) = x(u - 3 + 5) = x(u + 2) \). This allows you to write the integral as \( \int \frac{x(u + 2)}{u^{2}} \, dx \).
Replace \( x \, dx \) with \( \frac{du}{2} \) from the substitution step, so the integral becomes \( \int \frac{u + 2}{u^{2}} \cdot \frac{du}{2} = \frac{1}{2} \int \frac{u + 2}{u^{2}} \, du \).
Split the integral into simpler terms: \( \frac{1}{2} \int \left( \frac{u}{u^{2}} + \frac{2}{u^{2}} \right) du = \frac{1}{2} \int \left( \frac{1}{u} + 2u^{-2} \right) du \). Now, integrate each term separately using the power rule and logarithmic integration.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Integration of Rational Functions

This involves integrating functions expressed as the ratio of two polynomials. Techniques often include polynomial division, substitution, or partial fraction decomposition to simplify the integral into manageable parts.
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Intro to Rational Functions

Substitution Method

A technique where a part of the integral is replaced with a new variable to simplify the expression. For example, setting u = denominator or a function inside the integral can transform the integral into a standard form.
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Euler's Method

Polynomial Division and Simplification

When the degree of the numerator is equal to or higher than the denominator, dividing polynomials can simplify the integrand. This step often precedes substitution or partial fractions to make integration straightforward.
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Taylor Polynomials