Skip to main content
Ch. 8 - Integration Techniques
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Not the one you use?Change textbook
Chapter 8, Problem 8.R.15

2–74. Integration techniques Use the methods introduced in Sections 8.1 through 8.5 to evaluate the following integrals.
15. ∫ (from 1 to 2) (3x⁵ + 48x³ + 3x² + 16)/(x³ + 16x) dx

Verified step by step guidance
1
Step 1: Simplify the integrand by factoring the denominator. The denominator is \(x^3 + 16x\), which can be factored as \(x(x^2 + 16)\). Rewrite the integrand as \((3x^5 + 48x^3 + 3x^2 + 16) / (x(x^2 + 16))\).
Step 2: Break the integrand into partial fractions. Express the numerator \(3x^5 + 48x^3 + 3x^2 + 16\) as a sum of terms that can be divided by \(x(x^2 + 16)\). This involves finding constants \(A, B, C\) such that \(\frac{A}{x} + \frac{Bx + C}{x^2 + 16}\) equals the original fraction.
Step 3: Solve for the constants \(A, B, C\) by equating coefficients after multiplying through by the denominator \(x(x^2 + 16)\). This step involves algebraic manipulation to match terms on both sides of the equation.
Step 4: Integrate each term separately. The term \(\frac{A}{x}\) integrates to \(A \ln|x|\), and the term \(\frac{Bx + C}{x^2 + 16}\) can be split further into simpler integrals using substitution techniques or standard integral formulas for rational functions.
Step 5: Evaluate the definite integral by substituting the limits of integration (from \(x = 1\) to \(x = 2\)) into the antiderivative obtained in Step 4. Simplify the result to complete the solution.

Verified video answer for a similar problem:

This video solution was recommended by our tutors as helpful for the problem above.
Video duration:
7m
Was this helpful?

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Integration Techniques

Integration techniques are methods used to find the integral of a function. Common techniques include substitution, integration by parts, and partial fraction decomposition. Understanding these methods is crucial for evaluating complex integrals, as they allow for simplification and easier computation.
Recommended video:
06:18
Integration by Parts for Definite Integrals

Definite Integrals

A definite integral calculates the area under a curve between two specified limits. It is represented as ∫ from a to b f(x) dx, where 'a' and 'b' are the bounds of integration. The result of a definite integral is a numerical value that represents the accumulated quantity over the interval.
Recommended video:
05:43
Definition of the Definite Integral

Polynomial Functions

Polynomial functions are expressions that involve variables raised to whole number powers, combined using addition, subtraction, and multiplication. In the given integral, the numerator and denominator are polynomials, and understanding their behavior is essential for applying integration techniques effectively, especially when simplifying the integrand.
Recommended video:
07:00
Taylor Polynomials