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Ch. 4 - Applications of Derivatives
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Not the one you use?Change textbook
Chapter 4, Problem 4.7.63b

Checking Antiderivative Formulas


Right, or wrong? Say which for each formula and give a brief reason for each answer.


∫xsinx dx = -x cos x + C

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1
Recall the integration by parts formula: \(\int u \, dv = uv - \int v \, du\).
Identify parts for integration by parts: let \(u = x\) (so \(du = dx\)) and \(dv = \sin x \, dx\) (so \(v = -\cos x\)).
Apply the formula: \(\int x \sin x \, dx = -x \cos x - \int (-\cos x) \, dx = -x \cos x + \int \cos x \, dx\).
Integrate \(\int \cos x \, dx\) to get \(\sin x\), so the full antiderivative is \(-x \cos x + \sin x + C\).
Compare this with the given formula \(\int x \sin x \, dx = -x \cos x + C\); since the \(\sin x\) term is missing, the given formula is incorrect.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Antiderivative (Indefinite Integral)

An antiderivative of a function f(x) is another function F(x) whose derivative is f(x). The indefinite integral symbol ∫ represents the family of all antiderivatives, including a constant of integration C, since differentiation of a constant is zero.
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Integration by Parts

Integration by parts is a technique used to integrate products of functions. It is based on the product rule for differentiation and follows the formula ∫u dv = uv - ∫v du, where u and dv are parts of the original integrand chosen to simplify the integral.
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Verification of Antiderivatives

To verify if a given formula is an antiderivative, differentiate the proposed function and check if the result matches the original integrand. This method confirms correctness by reversing the integration process.
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