Exercises 41–60 contain rational equations with variables in denominators. For each equation, a. write the value or values of the variable that make a denominator zero. These are the restrictions on the variable. b. Keeping the restrictions in mind, solve the equation. 4/x = 5/2x + 3
Table of contents
- 0. Review of Algebra4h 18m
- 1. Equations & Inequalities3h 18m
- 2. Graphs of Equations1h 43m
- 3. Functions2h 17m
- 4. Polynomial Functions1h 44m
- 5. Rational Functions1h 23m
- 6. Exponential & Logarithmic Functions2h 28m
- 7. Systems of Equations & Matrices4h 5m
- 8. Conic Sections2h 23m
- 9. Sequences, Series, & Induction1h 22m
- 10. Combinatorics & Probability1h 45m
1. Equations & Inequalities
Linear Equations
Problem 46
Textbook Question
Solve each formula for the specified variable. Assume that the denominator is not 0 if variables appear in the denominator. s = 1/2gt², for g (distance traveled by a falling object)
Verified step by step guidance1
Start with the given formula: \(s = \frac{1}{2} g t^{2}\).
To isolate \(g\), first eliminate the fraction by multiplying both sides of the equation by 2: \$2s = g t^{2}$.
Next, to solve for \(g\), divide both sides of the equation by \(t^{2}\) (assuming \(t \neq 0\)): \(\frac{2s}{t^{2}} = g\).
Rewrite the equation to clearly express \(g\) as the subject: \(g = \frac{2s}{t^{2}}\).
This is the formula for \(g\) in terms of \(s\) and \(t\).
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Solving Formulas for a Specific Variable
This involves rearranging an equation to isolate the desired variable on one side. It requires using inverse operations such as multiplication, division, addition, subtraction, and taking roots to rewrite the formula in terms of the specified variable.
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Understanding Variables and Constants in Physics Formulas
In the formula s = 1/2gt², s represents distance, g is acceleration due to gravity, and t is time. Recognizing which variables are constants or given values helps in correctly manipulating the formula and interpreting the physical meaning.
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Solving Quadratic Equations Using The Quadratic Formula
Handling Exponents and Square Roots
Since t is squared in the formula, solving for g requires understanding how to deal with exponents. This often involves isolating the squared term and then applying square roots or squaring both sides to simplify the equation.
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Imaginary Roots with the Square Root Property
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