How many fluorine atoms are present in 5.85 g of C 2 F 4 ?

Hey everyone welcome back. So let's get started with this video. So here they want us to calculate the number of carbon atoms in 26. g of butane And we're told the mother mass of butane is 58. g per mole. Okay, so here we're told that there's 26.3 g of butane. Therefore that's going to be what we're going to start with. So it's going to be grams. Then from grams are going to want to go to moles And how are we going to get 2Molds? That is by using the molar mass of beauty in which we're actually told it's 58 .1 g per mole. Okay. And then for most we're going to want to find the moles of carbon in the formula of butane. Once again, we're going to look here and that's how we're going to find the moles of carbon. And then finally we're going to go to the number of carbon atoms. So Adams and we're going to go to their using avocados number Which is 6.02, 2 times 10 to the 23. Okay, so let's go ahead and start our store kilometer. So then we're going to start with the Graham's given, which is 26 0.3 grams of butane C four H 10. Okay, so here we're going to use the molar mass, which we're told is 58 .1g of beauty for one more C four H 10. Okay, so then for moles, we're going to find the moles of carbon. So then one more beauty. See for age 10 contains four moles of carbon. So four months. See, okay, finally we're going to go to atoms by using over gorgeous number. So then one more carbon is 6.0-2 Times 10 to the Adams of carbon. So then grams cancel out moles, cancel out moles of carbon cancel and we get Adams of carbon. We do the math and it's one 09 times 10 To the 24 atoms of carbon. Okay, thank you for watching. I hope this helped. And I'll see you in the next video.

Ch.3 - Molecules, Compounds & Chemical Equations

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Tro 4th Edition

Ch.3 - Molecules, Compounds & Chemical Equations

Problem 85

Chapter 3, Problem 85

How many fluorine atoms are present in 5.85 g of C₂F₄?

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Determine the molar mass of C2F4. Carbon (C) has an atomic mass of approximately 12.01 g/mol and fluorine (F) has an atomic mass of approximately 19.00 g/mol. The molar mass of C2F4 is calculated as: (2 \times 12.01) + (4 \times 19.00) g/mol.

Calculate the number of moles of C2F4 in 5.85 g using the formula: \text{moles} = \frac{\text{mass}}{\text{molar mass}}.

Each molecule of C2F4 contains 4 fluorine atoms. To find the total number of fluorine atoms, multiply the number of moles of C2F4 by Avogadro's number (6.022 \times 10^{23} \text{ molecules/mol}) and then by 4 (since each molecule has 4 fluorine atoms).

The calculation for the total number of fluorine atoms is: \text{total fluorine atoms} = \text{moles of C2F4} \times 6.022 \times 10^{23} \times 4.

This will give you the total number of fluorine atoms present in 5.85 g of C2F4.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Molar Mass

Molar mass is the mass of one mole of a substance, typically expressed in grams per mole (g/mol). For C2F4, the molar mass is calculated by summing the atomic masses of its constituent elements: carbon (C) and fluorine (F). This value is essential for converting between grams and moles, which is necessary to determine the number of atoms in a given mass of the compound.

Avogadro's Number

Avogadro's number, approximately 6.022 x 10^23, is the number of particles (atoms, molecules, etc.) in one mole of a substance. This constant allows chemists to relate the macroscopic scale of substances (grams) to the microscopic scale (individual atoms or molecules). In this question, it will be used to find the number of fluorine atoms from the moles of C2F4.

Stoichiometry

Stoichiometry is the calculation of reactants and products in chemical reactions based on the conservation of mass. In this context, it involves determining the ratio of fluorine atoms to C2F4 molecules. Since each molecule of C2F4 contains four fluorine atoms, stoichiometry will help in calculating the total number of fluorine atoms present in the given mass of the compound.

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How many fluorine atoms are present in 5.85 g of C2F4?

Verified video answer for a similar problem:

Key Concepts

Molar Mass

Avogadro's Number

Stoichiometry

How many fluorine atoms are present in 5.85 g of C₂F₄?