In a survey of 800800 randomly selected credit card numbers, 9292 of the last digits are fives. If the digits are randomly distributed, the proportion of fives should be 0.10.1. Construct a 95%95\% confidence interval for the proportion of fives. Does this interval support the claim that the true proportion is 0.10.1?

0.0929μ0.13710.0929Yes, the claim is supported since 0.10.1 lies within the interval

0.1050μ0.12500.1050No, the claim is not supported

0.1000μ0.12000.1000Yes, the claim is supported since 0.10.1 lies within the interval

0.0800μ0.09500.0800No, the claim is not supported

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Problem 31Multiple Choice

In a survey of $800$ randomly selected credit card numbers, $92$ of the last digits are fives. If the digits are randomly distributed, the proportion of fives should be $0.1$ . Construct a $95 percent sign$ confidence interval for the proportion of fives. Does this interval support the claim that the true proportion is $0.1$ ?

$0.0929 is less than mu is less than 0.1371$

Yes, the claim is supported since $0.1$ lies within the interval

$0.1050 is less than mu is less than 0.1250$

No, the claim is not supported

$0.1000 is less than mu is less than 0.1200$

Yes, the claim is supported since $0.1$ lies within the interval

$0.0800 is less than mu is less than 0.0950$

No, the claim is not supported

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