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Ch. 4 - Applications of Derivatives
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Not the one you use?Change textbook
Chapter 4, Problem 4.7.60

Checking Antiderivative Formulas


Verify the formulas in Exercises 57–62 by differentiation.


∫csc²((x − 1)/3)dx = −3cot((x − 1)/3) + C

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1
Identify the given antiderivative formula: \(\int \csc^{2}\left(\frac{x - 1}{3}\right) \, dx = -3 \cot\left(\frac{x - 1}{3}\right) + C\).
Recall that to verify an antiderivative, you differentiate the right-hand side and check if you get the original integrand.
Differentiate the function \(-3 \cot\left(\frac{x - 1}{3}\right)\) using the chain rule. Start by differentiating \(\cot(u)\) where \(u = \frac{x - 1}{3}\).
Use the derivative formula \(\frac{d}{du} \cot(u) = -\csc^{2}(u)\), so \(\frac{d}{dx} \cot\left(\frac{x - 1}{3}\right) = -\csc^{2}\left(\frac{x - 1}{3}\right) \cdot \frac{d}{dx} \left(\frac{x - 1}{3}\right)\).
Calculate \(\frac{d}{dx} \left(\frac{x - 1}{3}\right) = \frac{1}{3}\), then multiply all parts together and simplify to confirm the derivative equals \(\csc^{2}\left(\frac{x - 1}{3}\right)\), which verifies the formula.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Antiderivatives and Indefinite Integrals

An antiderivative of a function is another function whose derivative equals the original function. Indefinite integrals represent the family of all antiderivatives and include a constant of integration, C, since differentiation of a constant is zero.
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Introduction to Indefinite Integrals

Differentiation of Composite Functions (Chain Rule)

The chain rule is used to differentiate composite functions, where one function is inside another. It states that the derivative of f(g(x)) is f'(g(x)) multiplied by g'(x). This is essential when verifying antiderivatives involving expressions like (x - 1)/3.
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The Chain Rule for 3+ Functions

Derivatives of Trigonometric Functions

Knowing the derivatives of basic trig functions like cotangent and cosecant squared is crucial. For example, the derivative of cot(u) is -csc²(u) times the derivative of u. This knowledge helps verify if the given antiderivative formula is correct by differentiation.
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Derivatives of Other Inverse Trigonometric Functions
Related Practice
Textbook Question

Sketch the graphs of the rational functions in Exercises 53–60.


𝓍²

y = ------------------

𝓍² ― 4

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Textbook Question

Checking the Mean Value Theorem


Which of the functions in Exercises 7–12 satisfy the hypotheses of the Mean Value Theorem on the given interval, and which do not? Give reasons for your answers.


f(x) = {x² − x, −2 ≤ x ≤−1

2x² − 3x − 3, −1 < x ≤ 0

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Textbook Question

56. Airplane landing path An airplane is flying at altitude H when it begins its descent to an airport runway that is at horizontal ground distance L from the airplane, as shown in the accompanying figure. Assume that the landing path of the airplane is the graph of a cubic polynomial function y = ax^3+bx^2+cx+d, where y(-L)= H and y(0)=0.

a. What is dy/dx at x = 0?

b. What is dy/dx at x = -L?

c. Use the values for dy/dx at x = 0 and x =- L together with y(0) = 0 and y(-L) = H to show that y(x)=H[2(x/L)^3+3(x/L)^2]

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Textbook Question

Absolute Extrema on Finite Closed Intervals


In Exercises 21–36, find the absolute maximum and minimum values of each function on the given interval. Then graph the function. Identify the points on the graph where the absolute extrema occur, and include their coordinates.


g(x) = √(4 − x²), −2 ≤ x ≤ 1

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Textbook Question

The 8-ft wall shown here stands 27 ft from the building. Find the length of the shortest straight beam that will reach to the side of the building from the ground outside the wall.

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Textbook Question

Finding Indefinite Integrals


In Exercises 17–56, find the most general antiderivative or indefinite integral. You may need to try a solution and then adjust your guess. Check your answers by differentiation.


∫2x(1 − x⁻³) dx

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