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Ch. 4 - Exponential and Logarithmic Functions
Blitzer - College Algebra 8th Edition
Blitzer8th EditionCollege AlgebraISBN: 9780136970514Not the one you use?Change textbook
Chapter 5, Problem 24

Evaluate each expression without using a calculator. log3 27

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1
Recognize that the expression is \( \log_{3} 27 \), which asks: "To what power must 3 be raised to get 27?"
Rewrite 27 as a power of 3. Since \( 27 = 3^3 \), substitute this into the logarithm: \( \log_{3} 3^3 \).
Use the logarithmic identity \( \log_{a} a^x = x \) to simplify the expression.
Apply the identity to get \( \log_{3} 3^3 = 3 \).
Conclude that the value of \( \log_{3} 27 \) is the exponent 3, since \( 3^3 = 27 \).

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Logarithm Definition

A logarithm answers the question: to what exponent must the base be raised to produce a given number? For example, log base 3 of 27 asks, '3 raised to what power equals 27?' Understanding this definition is essential to evaluate logarithmic expressions.
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Exponentiation and Powers

Recognizing powers of numbers helps simplify logarithms. Since 27 is 3 raised to the 3rd power (3^3 = 27), this relationship allows direct evaluation of log base 3 of 27 by identifying the exponent.
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Properties of Logarithms

Logarithms have properties such as log_b(b^x) = x, which means the logarithm of a base raised to an exponent is just that exponent. This property simplifies evaluating expressions like log_3(27) by converting the problem into finding the exponent.
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