Find ƒ+g, ƒ- g, ƒg and ƒ/g. Determine the domain for each function. f(x) = 3 − x², g(x) = x² + 2x − 15
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- 0. Review of Algebra4h 18m
- 1. Equations & Inequalities3h 18m
- 2. Graphs of Equations1h 43m
- 3. Functions2h 17m
- 4. Polynomial Functions1h 44m
- 5. Rational Functions1h 23m
- 6. Exponential & Logarithmic Functions2h 28m
- 7. Systems of Equations & Matrices4h 5m
- 8. Conic Sections2h 23m
- 9. Sequences, Series, & Induction1h 22m
- 10. Combinatorics & Probability1h 45m
3. Functions
Intro to Functions & Their Graphs
Problem 43c
Textbook Question
Find fg and determine the domain for each function. f(x)= = (5x+1)/(x² - 9), g(x) = (4x -2)/(x² - 9)
Verified step by step guidance1
Step 1: Understand the problem. You are tasked with finding the composition of two functions, fg(x), which means f(g(x)). Additionally, you need to determine the domain of the resulting function. The given functions are f(x) = (5x + 1) / (x² - 9) and g(x) = (4x - 2) / (x² - 9).
Step 2: Substitute g(x) into f(x) to find fg(x). Replace every instance of x in f(x) with g(x). This gives fg(x) = (5 * [(4x - 2) / (x² - 9)] + 1) / ([(4x - 2) / (x² - 9)]² - 9).
Step 3: Simplify the numerator of fg(x). Distribute the 5 to the terms in g(x), then add 1. This results in the numerator: (5 * (4x - 2) / (x² - 9)) + 1 = (20x - 10) / (x² - 9) + 1. Combine terms over a common denominator.
Step 4: Simplify the denominator of fg(x). Square g(x) to get [(4x - 2) / (x² - 9)]², then subtract 9. This results in: [(4x - 2)² / (x² - 9)²] - 9. Combine terms over a common denominator.
Step 5: Determine the domain of fg(x). The domain is restricted by values of x that make the denominator of f(x), g(x), or fg(x) equal to zero. For both f(x) and g(x), the denominator x² - 9 = 0 when x = ±3. Additionally, check for any restrictions introduced by fg(x). Exclude these values from the domain.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Function Composition
Function composition involves combining two functions, where the output of one function becomes the input of another. In this case, fg means f(g(x)), which requires substituting g(x) into f(x). Understanding how to perform this substitution is crucial for finding the composite function.
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Function Composition
Domain of a Function
The domain of a function is the set of all possible input values (x-values) for which the function is defined. For rational functions like f(x) and g(x), the domain is restricted by values that make the denominator zero. Identifying these restrictions is essential for determining the valid inputs for the composite function fg.
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Domain Restrictions of Composed Functions
Rational Functions
Rational functions are ratios of polynomials, expressed in the form f(x) = P(x)/Q(x), where P and Q are polynomials. The behavior of these functions, including their asymptotes and discontinuities, is influenced by the zeros of the denominator. Understanding the properties of rational functions is key to analyzing their domains and compositions.
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Intro to Rational Functions
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