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Ch. 3 - Cell Division and Chromosome Heredity
Sanders - Genetic Analysis: An Integrated Approach 3rd Edition
Sanders3rd EditionGenetic Analysis: An Integrated ApproachISBN: 9780135564172Not the one you use?Change textbook
Chapter 3, Problem 33b

Form a small discussion group and decide on the most likely genetic explanation for each of the following situations;
Cross A, performed by Morgan and shown in the figure below, is between a mutant male fruit fly with white eyes and a female fruit fly from a pure-breeding, red-eye stock. The figure shows that 1237 F1 progeny were produced, all of them with red eyes. In reality, this isn't entirely true. Among the 1237 F1 progeny were 3 male flies with white eyes. Give two possible explanations for the appearance of these white-eyed males.
Diagram showing two fruit fly crosses illustrating inheritance of eye color with parental, F1, and F2 generations and phenotype ratios.

Verified step by step guidance
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Step 1: Understand the genetic basis of eye color in fruit flies as studied by Morgan. The white eye mutation is X-linked recessive, meaning the gene responsible is located on the X chromosome, and the white-eye phenotype appears in males if they inherit the mutant X chromosome, since males have only one X chromosome (XY).
Step 2: Analyze the cross described: a mutant white-eyed male (X^w Y) crossed with a pure-breeding red-eyed female (X^+ X^+). The expected F1 progeny should all have red eyes because females provide the dominant red-eye allele (X^+), and males inherit the X^+ from their mother, resulting in red eyes.
Step 3: Consider why 3 white-eyed males appeared among 1237 F1 progeny. One possible explanation is a rare event of nondisjunction during meiosis in the female parent, leading to sperm or eggs with abnormal sex chromosome numbers, which could produce males with the mutant X chromosome.
Step 4: Another possible explanation is a spontaneous mutation occurring in the X chromosome of some F1 males, converting the red-eye allele to the white-eye allele, resulting in white-eyed males despite the expected genotype.
Step 5: Summarize that these explanations involve either chromosomal abnormalities (nondisjunction) or new mutations, both of which can cause unexpected phenotypes in genetic crosses, especially when dealing with X-linked traits.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Sex-Linked Inheritance

Sex-linked inheritance refers to genes located on sex chromosomes, often the X chromosome in fruit flies. Since males have one X and one Y chromosome, recessive mutations on the X chromosome, like the white-eye mutation, are more likely to be expressed in males. This explains why white eyes often appear in male progeny when inherited from carrier females.
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Sex-Linked Genes

Mutation and Reversion

Mutations are changes in the DNA sequence that can alter gene function. Occasionally, a rare reversion mutation can restore the original gene function, causing unexpected phenotypes. In this case, a few white-eyed males might arise due to new mutations or reversions affecting the eye color gene.
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Nondisjunction and Chromosomal Abnormalities

Nondisjunction is the failure of chromosomes to separate properly during meiosis, leading to gametes with abnormal chromosome numbers. This can produce males with unusual combinations of sex chromosomes, such as XXY or XO, potentially causing unexpected expression of X-linked traits like white eyes in males.
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Related Practice
Textbook Question

From a piece of blank paper, cut out three sets of four cigar-shaped structures (a total of 12 structures). These will represent chromatids. Be sure each member of a set of four chromatids has the same length and girth. In set one, label two chromatids 'A' and two chromatids 'a.' Cut each of these chromatids about halfway across near their midpoint and slide the two 'A' chromatids together at the cuts to form a single set of attached sister chromatids. Do the same for the 'a' chromatids. In the second set of four chromatids, label two 'B' and two 'b.' Cut and slide these together as you did for the first set, joining the 'B' chromatids together and the 'b' chromatids together. Repeat this process for the third set of chromatids, labeling them as 'D' and 'd.' You now have models for three pairs of homologous chromosomes, for a total of six chromosomes. Repeat steps (h) through (l) for the alternative alignment of chromosomes you identified in step (g).

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Textbook Question

From a piece of blank paper, cut out three sets of four cigar-shaped structures (a total of 12 structures). These will represent chromatids. Be sure each member of a set of four chromatids has the same length and girth. In set one, label two chromatids 'A' and two chromatids 'a.' Cut each of these chromatids about halfway across near their midpoint and slide the two 'A' chromatids together at the cuts to form a single set of attached sister chromatids. Do the same for the 'a' chromatids. In the second set of four chromatids, label two 'B' and two 'b.' Cut and slide these together as you did for the first set, joining the 'B' chromatids together and the 'b' chromatids together. Repeat this process for the third set of chromatids, labeling them as 'D' and 'd.' You now have models for three pairs of homologous chromosomes, for a total of six chromosomes. Combining your work in steps (f) through (m), provide a written explanation of the connection between meiotic cell division and Mendel's law of independent assortment.

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Textbook Question

Form a small discussion group and decide on the most likely genetic explanation for each of the following situations;

A man who has red–green color blindness and a woman who has complete color vision have a son with red–green color blindness. What are the genotypes of these three people, and how do you explain the color blindness of the son?

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Textbook Question

Duchenne muscular dystrophy (DMD; OMIM 310200) and Becker muscular dystrophy (BMD; OMIM 300376) are both X-linked recessive conditions that result from different mutations of the same gene, known as dystrophin, on the long arm of the chromosome. BMD and DMD are quite different clinically. DMD is a very severe disorder that first appears at a young age, progresses rapidly, and is often fatal in the late teens to 20s. BMD, on the other hand, is much milder. Often symptoms don't first appear until the 40s or 50s, the progression of the disease is slow, and fatalities due to BMD are infrequent. Go to https://www.ncbi.nlm.nih/omim and survey the information describing the gene mutations causing these two conditions. Discuss the information you find with a few others in a small group, and write a single summary explaining your findings.

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Textbook Question

Red–green color blindness is a relatively common condition found in about 8% of males in the general population. From this, population, biologists estimate that 8% is the frequency of X chromosomes carrying a mutation of the gene encoding red and green color vision. Based on this frequency, determine the approximate frequency with which you would expect females to have red–green color blindness. Explain your reasoning.

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