Identify the following molecules as an ester, a carboxylic acid, or an amide, and write both the condensed and line-structural formula for each.
a.

Question

Identify the following molecules as an ester, a carboxylic acid, or an amide, and write both the condensed and line-structural formula for each.

a.

Accepted Answer

Hello, everyone. Today, we have the following problem is the given compound in ether, a carboxylic acid or an amide also draw its condensed and line angle structures. Well, seeing here that we have the presence of a nitrogen in the compound, we can conclude that this is an amide and not a carboxylic acid or an ester. And so an amide contains a carbonyl group that is directly attached to a nitrogen atom. And so if we were to draw the structure out, we can note that it has five carbons. So we can just draw our five carbons in a straight line. And what we can do is we can make one of the end carbons, the carbon neal carbon of the M I. And so essentially that means that we will draw the oxygen onto that carbon carbon as well as our amino group, which makes this functional group an A I. And then we essentially count the number of additional hydrogens that we need or that we can place, we see that we've already used two. So we can only use nine. So if we follow the octet rule, each of the following carbons gets two hydrogens. And then we note that we have three more that we can use. So we will make this other end in carbon a methyl group. And so this was essentially our structured or structural form of this compound. So now that we have this, we can essentially construct our condensed and our line angle structures. So as far as our condensed structures go, we essentially will group these such in a way that we will have one carbon labeled out and we will draw the number of hydrogens attached to it, we will do the same for the subsequent carbons. So, from left to right, if we have carbons, 1234 and five, we have carbon two next and carbon two has two hydrogens, carbon three also has two hydrogens as does carbon four. Now, carbon five is a little different. However, when we want to represent a double bond with a, between a carbon and a hyd, between a carbon and oxygen, we simply will just draw that oxygen next to the carbon followed by the amine group. And so this will be our condensed form. Now comes the line angle structure. And to represent this, we will, this is essentially the skeletal formula of the compound. And so we will omit any hydrogens that are not attached to a hetero atom such as nitrogen. So what we will do is we will draw a string of five carbon atoms noting that each point or vertex represents a carbon atom. And then now that we have our five carbon atoms, we go from left to right. We have carbons one, we have carbons 5432 and one. And on carbon one, we will construct our amide group by having a double body oxygen on carbon one as well as our a meal group. And so with that, we have essentially determined that this compound wasn't amide constructed its condensed and line angle structures. And with that, we have solved the problem overall, I hope this helped. And until next time.

Identify the following molecules as an ester, a carboxylic acid, or an amide, and write both the condensed and line-structural formula for each.
a. <IMAGE>

Verified video answer for a similar problem:

Key Concepts

Ester

Carboxylic Acid

Amide