A scientist measures the concentration of a chemical in 2525 water samples and finds a sample mean of 13.6 mg/L13.6~\text{mg/L} with a sample standard deviation of 3.2 mg/L3.2~\text{mg/L}. Construct the 98%98\% confidence interval for the population mean using the tt-distribution. Assume the population of concentrations is normally distributed.

12.0 mg/Lμ15.2 mg/L12.0~\text{mg/L}\lt\mu\lt{15.2~\text{mg/L}}

11.4 mg/Lμ15.8 mg/L11.4~\text{mg/L}\lt\mu\lt{15.8~\text{mg/L}}

12.8 mg/Lμ14.4 mg/L12.8~\text{mg/L}\lt\mu\lt{14.4~\text{mg/L}}

10.9 mg/Lμ16.3 mg/L10.9~\text{mg/L}\lt\mu\lt{16.3~\text{mg/L}}

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Mean
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Sampling Distribution of the Sample Mean and Central Limit Theorem
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Sampling Distribution of Sample Proportion
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Confidence Intervals for Population Mean

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Problem 141Multiple Choice

A scientist measures the concentration of a chemical in $25$ water samples and finds a sample mean of $13.6 mg slash cap L$ with a sample standard deviation of $3.2 mg slash cap L$ . Construct the $98 percent sign$ confidence interval for the population mean using the $t$ -distribution. Assume the population of concentrations is normally distributed.

$12.0 mg slash cap L is less than mu is less than 15.2 mg slash cap L$

$11.4 mg slash cap L is less than mu is less than 15.8 mg slash cap L$

$12.8 mg slash cap L is less than mu is less than 14.4 mg slash cap L$

$10.9 mg slash cap L is less than mu is less than 16.3 mg slash cap L$

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