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Ch. 8 - Integration Techniques
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Not the one you use?Change textbook
Chapter 8, Problem 8.2.29

9–40. Integration by parts Evaluate the following integrals using integration by parts.
29. ∫ e⁻ˣ sin(4x) dx

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1
Identify the integral to solve: \(\int e^{-x} \sin(4x) \, dx\).
Recall the integration by parts formula: \(\int u \, dv = uv - \int v \, du\).
Choose \(u\) and \(dv\) wisely. For this integral, let \(u = \sin(4x)\) and \(dv = e^{-x} dx\).
Compute \(du\) and \(v\): differentiate \(u\) to get \(du = 4 \cos(4x) dx\), and integrate \(dv\) to get \(v = -e^{-x}\).
Apply the integration by parts formula: substitute \(u\), \(v\), \(du\) into \(\int u \, dv = uv - \int v \, du\), then simplify the resulting integral. You may need to apply integration by parts a second time or solve for the original integral algebraically.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Integration by Parts

Integration by parts is a technique derived from the product rule of differentiation. It transforms the integral of a product of functions into simpler integrals using the formula ∫u dv = uv - ∫v du. Choosing appropriate u and dv is crucial to simplify the integral effectively.
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Integration of Exponential and Trigonometric Functions

Integrals involving products of exponential and trigonometric functions often require repeated application of integration by parts. Recognizing patterns and using algebraic manipulation helps to solve these integrals, especially when the integral reappears during the process.
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Solving for the Original Integral

When integration by parts leads to an integral expression containing the original integral, algebraic techniques are used to isolate and solve for it. This method is common in integrals involving products of exponential and trigonometric functions, enabling the evaluation of otherwise complex integrals.
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