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Ch. 7 - Transcendental Functions
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Not the one you use?Change textbook
Chapter 7, Problem 7.6.102

Evaluate the integrals in Exercises 91–102.
102. ∫(from -1/3 to 1/√3)(cos(arctan 3x))/(1+9x²) dx

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Recognize that the integral involves the expression \( \cos(\arctan(3x)) \) and the denominator \( 1 + 9x^2 \). This suggests a trigonometric substitution related to the angle \( \theta = \arctan(3x) \).
Set \( \theta = \arctan(3x) \), which implies \( 3x = \tan(\theta) \). From this, express \( x \) in terms of \( \theta \): \( x = \frac{\tan(\theta)}{3} \).
Calculate the differential \( dx \) in terms of \( d\theta \). Since \( x = \frac{\tan(\theta)}{3} \), then \( dx = \frac{1}{3} \sec^2(\theta) d\theta \).
Rewrite the integral limits in terms of \( \theta \) by substituting the original \( x \) limits into \( \theta = \arctan(3x) \). For \( x = -\frac{1}{3} \), \( \theta = \arctan(-1) = -\frac{\pi}{4} \). For \( x = \frac{1}{\sqrt{3}} \), \( \theta = \arctan\left(3 \cdot \frac{1}{\sqrt{3}}\right) = \arctan(\sqrt{3}) = \frac{\pi}{3} \).
Substitute all parts into the integral: replace \( \cos(\arctan(3x)) \) with \( \cos(\theta) \), replace \( 1 + 9x^2 \) with \( 1 + \tan^2(\theta) = \sec^2(\theta) \), and replace \( dx \) with \( \frac{1}{3} \sec^2(\theta) d\theta \). Simplify the integrand and integral accordingly before integrating with respect to \( \theta \) from \( -\frac{\pi}{4} \) to \( \frac{\pi}{3} \).

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Integration of Composite Functions

This involves integrating functions composed of other functions, such as trigonometric functions of inverse trigonometric functions. Recognizing the inner function and its derivative helps in applying substitution methods to simplify the integral.
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Inverse Trigonometric Functions and Their Properties

Understanding the definition and properties of inverse trigonometric functions like arctan is crucial. For example, arctan(x) returns an angle whose tangent is x, which allows rewriting expressions involving arctan in terms of trigonometric identities.
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Substitution Method in Definite Integrals

The substitution method replaces a complicated expression with a single variable to simplify integration. When dealing with definite integrals, the limits must be adjusted according to the substitution to correctly evaluate the integral.
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Related Practice
Textbook Question

Since the hyperbolic functions can be expressed in terms of exponential functions, it is possible to express the inverse hyperbolic functions in terms of logarithms, as shown in the following table.

sinh⁻¹x = ln(x + √(x² + 1)), -∞ < x < ∞

cosh⁻¹x = ln(x + √(x² - 1)), x ≥ 1

tanh⁻¹x = (1/2)ln((1+x)/(1-x)), |x| < 1

sech⁻¹x = ln((1+√(1-x²))/x), 0 < x ≤ 1

csch⁻¹x = ln(1/x + √(1+x²)/|x|), x ≠ 1

coth⁻¹x = (1/2)ln((x+1)/(x-1)), |x| > 1

Use these formulas to express the numbers in Exercises 61–66 in terms of natural logarithms.

63. tanh⁻¹(-1/2)

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Textbook Question

25. First-order chemical reactions In some chemical reactions, the rate at which the amount of a substance changes with time is proportional to the amount present. For the change of δ-gluconolactone into gluconic acid, for example,

dy/dt = -0.6y

when t is measured in hours. If there are 100 grams of δ-gluconolactone present when t=0, how many grams will be left after the first hour?

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Textbook Question

In Exercises 25–36, find the derivative of y with respect to the appropriate variable.

31. y = cos⁻¹(x) - x sech⁻¹(x)

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Textbook Question

In Exercises 7–26, find the derivative of y with respect to x, t, or θ, as appropriate.

y = cos(e^(-θ^2))

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Textbook Question

In Exercises 115–126, use logarithmic differentiation or the method in Example 6 to find the derivative of y with respect to the given independent variable.

122. y = (ln x)^(ln x)

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Textbook Question

In Exercises 57–70, use logarithmic differentiation to find the derivative of y with respect to the given independent variable.

66. y = θsin(θ)/√(sec(θ))

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