In Exercises 15–58, find each product. (5−7x)(5+7x)

Question

Accepted Answer

This problem says determine the product at the given expression. Why? -3 times y plus three. I'm gonna go ahead and rewrite this real quick. We have y minus three times Y plus three. Now we're multiplying two expressions together. So we want to make use of what's called the foil technique. The foil technique states that we multiply the other our first terms, our outer terms, our inner terms and our last terms. So in the expression we can get all this information here. The first terms are the first terms that appear in each expression. So through the expression we have y minus three Y plus three. So the first term and our first question would be our way similarly and the other expression. It would be the other way. These are the terms that appear first expression. So we're gonna multiply those together. Why times what? Now we want the outer terms. The other terms are terms that appear on the outside of our entire group of expressions. So if you like our group of expressions. This wire right here on the left is on the outermost side to the left. The same for the three on the right is on the other side to the right. So we'll multiply those together. Why? Times three? So plus why? Times three? Now the winners are the same as the others were just using the inside instead of the outside. So the inside of this would be dated three And or what? So we have a -3 times Why? Finally our last terms are the last terms in each of our expressions. so calculated first we will do our less other words are negative three and our positive three. So you can multiply those together. Now we have our list of things here. I'm gonna go ahead and simplify this by multiplying all these together. So first we have a Y. Times Y. That is just a white square. Then we have a three times away which is just three way. Now we have a negative three times Y which is negative three way. And finally we have negative three times three which is negative nine. Now we have to simplify once more to get our final answer smoothly combine like terms. So a light term is just duplicates of the same terms such as our wise here we both have Wise and both of these expressions so we're gonna simplify those by combining these terms. We have three Y. And a negative three Y. Well three Y. And later three Y. We add those together. They will cancel each other out which means this just goes to zero by square. Doesn't have any more terms. There's no other terms to come out with the nine. So we just drop those down. One squared minus nine. Now there's no more things to combine which means that our answer is just y squared minus nine. Our answer is answer. D Okay I hope to help you solve the problem. Thank you for watching. Goodbye

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