A chemist wants to make 5.5 L of a 0.300 M CaCl 2 solution. What mass of CaCl 2 (in g) should the chemist use?

everyone to hear what? Ask. Chocolate and Masterman using iodide That has made it to prepare 0.2 l A 4.59 Mueller of magnesium iodide solution. Recall that polarity. It was moss of solute. But by leaders of solution. Since we're giving the volume and the clarity you can use the maturity equation to solve for moles We have 4.59 Mueller. There's going to be equal to X Divided by 0. leaders. So if you must have 4.59 my word Times 0.2 leaders. Is that equal to X? I'm gonna get X. Is equal to 0.918 moles. And now since we have moles we can convert from moles of magnesium iodide to find grams of magnesium iodide 0. 18 bob a magnesium iodine. And in one mall mechanism I died we had the molar mass which we need to find. The molar mass is equal to the math of Magnesium which is .305g plus two Because there's two iodine comes a mass of iodine Which is .904 gramps. And this will give us 278 113 grams of magnesium. I died. So now this will give us 255 grams. Thanks for watching my video and I hope it was helpful

Ch.4 - Chemical Quantities & Aqueous Reactions

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Tro 4th Edition

Ch.4 - Chemical Quantities & Aqueous Reactions

Problem 60

Chapter 4, Problem 60

A chemist wants to make 5.5 L of a 0.300 M CaCl₂ solution. What mass of CaCl₂ (in g) should the chemist use?

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Determine the number of moles of CaCl_2 needed using the formula: moles = molarity \times volume.

Convert the volume from liters to moles using the given molarity (0.300 M) and volume (5.5 L).

Calculate the moles of CaCl_2 by multiplying the molarity (0.300 M) by the volume (5.5 L).

Find the molar mass of CaCl_2 by adding the atomic masses of calcium (Ca) and chlorine (Cl) from the periodic table.

Calculate the mass of CaCl_2 by multiplying the moles of CaCl_2 by its molar mass.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Molarity (M)

Molarity is a measure of concentration defined as the number of moles of solute per liter of solution. It is expressed in moles per liter (mol/L). Understanding molarity is essential for calculating how much solute is needed to achieve a desired concentration in a given volume of solution.

Moles and Molar Mass

A mole is a unit that quantifies the amount of substance, equivalent to Avogadro's number (approximately 6.022 x 10²³ particles). The molar mass of a compound, calculated from the atomic masses of its constituent elements, allows for the conversion between grams and moles, which is crucial for determining how much of a substance is needed for a specific molarity.

Dilution and Solution Preparation

Dilution involves adding solvent to a concentrated solution to achieve a desired molarity. When preparing a solution, it is important to calculate the required mass of solute based on the desired molarity and volume, ensuring accurate and consistent results in chemical experiments.

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A chemist wants to make 5.5 L of a 0.300 M CaCl2 solution. What mass of CaCl2 (in g) should the chemist use?

Verified video answer for a similar problem:

Key Concepts

Molarity (M)

Moles and Molar Mass

Dilution and Solution Preparation

A chemist wants to make 5.5 L of a 0.300 M CaCl₂ solution. What mass of CaCl₂ (in g) should the chemist use?