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Ch. 25 - Quantitative Genetics and Multifactorial Traits
Klug - Concepts of Genetics  12th Edition
Klug12th EditionConcepts of Genetics ISBN: 9780135564776Not the one you use?Change textbook
Chapter 25, Problem 15

In a herd of dairy cows the narrow-sense heritability for milk protein content is 0.76, and for milk butterfat it is 0.82. The correlation coefficient between milk protein content and butterfat is 0.91. If the farmer selects for cows producing more butterfat in their milk, what will be the most likely effect on milk protein content in the next generation?

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1
Identify the key parameters given: narrow-sense heritability for milk protein content (\(h^2_{protein} = 0.76\)), narrow-sense heritability for milk butterfat (\(h^2_{butterfat} = 0.82\)), and the phenotypic correlation coefficient between the two traits (\(r_P = 0.91\)).
Understand that selecting for increased butterfat content will cause a correlated response in milk protein content due to the genetic correlation between the traits.
Recall the formula for the correlated response to selection: \(CR_Y = i \times h_Y \times r_A \times \sigma_Y\), where \(CR_Y\) is the correlated response in trait Y (milk protein), \(i\) is the selection intensity on trait X (butterfat), \(h_Y\) is the square root of heritability of trait Y, \(r_A\) is the genetic correlation between traits, and \(\sigma_Y\) is the phenotypic standard deviation of trait Y. Since \(i\) and \(\sigma_Y\) are not given, focus on the relationship between traits.
Calculate the genetic correlation (\(r_A\)) between milk protein and butterfat using the formula: \(r_A = \frac{r_P}{\sqrt{h^2_{protein} \times h^2_{butterfat}}}\). This step helps determine how strongly the traits are genetically linked.
Interpret the sign and magnitude of \(r_A\): a positive and high genetic correlation means that selecting for higher butterfat will likely increase milk protein content in the next generation as well.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Narrow-Sense Heritability

Narrow-sense heritability (h²) measures the proportion of phenotypic variance in a trait that is due to additive genetic factors. It predicts the response to selection because only additive effects are reliably passed from parents to offspring. A high h² indicates that selection will effectively change the trait in the next generation.
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Calculating Heritability

Genetic Correlation

Genetic correlation quantifies the degree to which two traits share common genetic influences. A positive correlation means that genes increasing one trait tend to increase the other. This implies that selection for one trait can cause a correlated response in the other, even if it is not directly selected.
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Descriptive Genetics

Correlated Response to Selection

Correlated response occurs when selection on one trait causes a change in another genetically correlated trait. The magnitude depends on heritabilities and the genetic correlation. In this case, selecting for higher butterfat will likely increase milk protein content due to their strong positive genetic correlation.
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Related Practice
Textbook Question

The mean and variance of plant height of two highly inbred strains (P₁ and P₂) and their progeny (F₁ and F₂) are shown here.


  Strain  Mean (cm)  Variance 

   P₁     34.2        4.2

   P₂     55.3        3.8

   F₁     44.2        5.6

   F₂     46.3       10.3


Calculate the broad-sense heritability () of plant height in this species.

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Textbook Question

A hypothetical study investigated the vitamin A content and the cholesterol content of eggs from a large population of chickens. The following variances (V) were calculated.

Calculate the narrow-sense heritability () for both traits.

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Textbook Question

A hypothetical study investigated the vitamin A content and the cholesterol content of eggs from a large population of chickens. The following variances (V) were calculated.

Which trait, if either, is likely to respond to selection?

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Textbook Question

In an assessment of learning in Drosophila, flies were trained to avoid certain olfactory cues. In one population, a mean of 8.5 trials was required. A subgroup of this parental population that was trained most quickly (mean=6.0) was interbred, and their progeny were examined. These flies demonstrated a mean training value of 7.5. Calculate realized heritability for olfactory learning in Drosophila.

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Textbook Question

Suppose you want to develop a population of Drosophila that would rapidly learn to avoid certain substances the flies could detect by smell. Based on the heritability estimate you obtained in Problem 16, do you think it would be worth doing this by artificial selection? Why or why not?

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Textbook Question

In a population of tomato plants, mean fruit weight is 60 g and is 0.3. Predict the mean weight of the progeny if tomato plants whose fruit averaged 80 g were selected from the original population and interbred.

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